Question

我有一个包含成员的表，我需要查找所有具有相同名称的成员。如何用SQL编写它？

这是表格：

create table Members( 
  MemberID char(13), 
  Name varchar(20),
  primary key(MemberID) 
)engine=innodb;


insert into Members(MemberID, Namn) values(’111’, ’John’);
insert into Members(MemberID, Namn) values(’222’, ’John’);
insert into Members(MemberID, Namn) values(’333’, ’Ralph’);
insert into Members(MemberID, Namn) values(’444’, ’Tony’);
insert into Members(MemberID, Namn) values(’555’, ’Ben’);

我需要的是为所有具有相同名称的成员提取MemberID - 在此示例中应返回111和222。

Answer 1

这会对你有所帮助。

SELECT
name, COUNT(*)
FROM
<Table Name>
GROUP BY
name
HAVING 
COUNT(*) > 1

Answer 2

SQL DEMO

您可以使用此查询来获得所需的结果：

select * from Members where Name in(
    select Name from Members
    group by Name having count(Name) > 1
)

Answer 3

WITH members_1 AS
(
    SELECT UPPER (name) AS name1
    FROM   members 
)
SELECT x.name1,y.memberid FROM 
(
    SELECT name1
    FROM members_1
    GROUP BY name1 
    HAVING COUNT(name1) > 1
) x 
JOIN members y ON UPPER(x.name1) = UPPER(y.name)

Answer 4

  select memberid 
    from 
    (
    select count(*) count,group_concat(memberid) memberid,name 
    from members group by name
    ) membertable
    where membertable.count>1

根据列查找重复记录

4 个答案: