Question

我尝试在表条件下获取数据然后我想选择如果在成员条件表中有condition_id我想打印出success_img否则打印失败我已经尝试

条件

any([1, 2, 3])
all([1, 2, 3])

会员条件

|---------------------|------------------|------------------|------------------|
|      id .           |      name        |  success_img     | unsuccess_img
|---------------------|------------------|------------------|------------------|
|          1          |     name1 .      |   success        | unsuccess
|---------------------|------------------|------------------|------------------|

这是我的HTML

|---------------------|------------------|------------------|------------------|
|      id .           |  condition_id    |  member_id       | add_by
|---------------------|------------------|------------------|------------------|
|          1          |     1 .   .      |   1 .            | admin
|---------------------|------------------|------------------|------------------|

这是我的控制器

<?php foreach ($data['getCoin'] as $item) { ?>
        <div class="skill-need-inner">
           <div class="skill-need-img">
            <?php 
            if ( !empty($data['condition_id'])) {
                if (in_array($item['condition_id'],$data['condition_id'])) {
            ?>
                    <img class="" src="<?php echo assets('uploads/'.$item['success']); ?>" alt="scucess" data-toggle="tooltip" data-placement="top" data-original-title="<?php echo $data['add_by']; ?>">
            <?php
                }  else {
            ?>
                    <img class="" src="<?php echo assets('uploads/'.$item['unsuccess']); ?>" alt="unsuccess" data-toggle="tooltip" data-placement="top" >
            <?php
                }
            }
            ?>
            </div>
        </div>

我的模特测试

 $data['getCoin'] = test::getInstance()->getCoin();
        $data['getCoinSuccess'] = test::getInstance()->getCoinSuccess(Session::get('member_id'));
        if ($data['getCoinSuccess']) {
            foreach ($data['getCoinSuccess'] as $itemSuccess) {
                $data['condition_id'][] = $itemSuccess['condition_id'];
                $data['add_by'][] = $itemSuccess['add_by'];
            }
        }

在我的尝试中只打印出img成功，但我怎样才能打印出add_by？现在我正在考虑加入表。我知道我的逻辑不好。初学者对此感到抱歉

Answer 1

我认为以下查询对您有用

SELECT * FROM member_condition 
INNER JOIN condition 
ON member_condition.condition_id = condition.id 
ORDER BY member_condition.condition_id DESC

如何在php中多次获取数据

1 个答案: