Question

Spoiler alert：我对Oracle很新我有四个表：注册，课程/部分，标准和成绩。

我们正在运行Honor Roll。我对前三个表有查询，这些表添加了满足荣誉要求所需的各种约束。然后我们看看成绩表。如果他们在有效课程中有有效的注册，符合有效标准，则计算他们的分数。如果他们的得分数量达到阈值，那么他们就会获得荣誉。

此代码未经过优化，可能会以更好/更紧凑的方式完成我确定 - 但是，它每年只能运行几次，所以我愿意权衡优化以增加人类的可读性，这样我就可以继续学习基础知识。到目前为止，我有：

WITH validCC (SELECT CC.ID AS CCID,
    CC.STUDENTID AS STUDENTID, 
    CC.SECTIONID AS SECTIONID, 
    CC.TERMID AS TERMID, 
    STUDENTS.DCID AS STUDENTSDCID
FROM CC
    INNER JOIN STUDENTS ON CC.STUDENTID = STUDENTS.ID
WHERE TERMID in (2700,2701)
    AND CC.SCHOOLID = 406;
),  --end validCC

validCrsSect (SELECT SECTIONS.ID AS SECTIONID,
    SECTIONS.DCID AS SECTIONSDCID,
    SECTIONS.EXCLUDEFROMHONORROLL AS SECTHR,
    COURSES.COURSE_NUMBER AS COURSE_NUMBER,
    COURSES.COURSE_NAME AS COURSE_NAME,
    COURSES.EXCLUDEFROMHONORROLL AS CRSHR
FROM SECTIONS
    INNER JOIN COURSES ON SECTIONS.COURSE_NUMBER = COURSES.COURSE_NUMBER AND SECTIONS.SCHOOLID = COURSES.SCHOOLID
WHERE SECTIONS.TERMID IN (2700,2701)
    AND SECTIONS.SCHOOLID = 406
    AND SECTIONS.EXCLUDEFROMHONORROLL = 0
    AND COURSES.EXCLUDEFROMHONORROLL = 0
), --end validCrsSect

validStandard (SELECT STANDARDID,
    IDENTIFIER,
    TRANSIENTCOURSELIST
FROM STANDARD
WHERE isActive = 1
    AND YEARID = 27
    AND ( instr (STANDARD.identifier, 'MHS.TS', 1 ,1) > 0     --Is a valid standard for this criteria:  MHS TS
        or STANDARD.identifier = 'MHTC.TS.2'                  --or MHTC TS
        or STANDARD.identifier = 'MHTC.TS.4'  )
), --end validStandard

--sgsWithChecks ( 
SELECT sgs.STANDARDGRADESECTIONID AS SGSID,
    sgs.STUDENTSDCID as STUDENTSDCID,
    sgs.STANDARDID AS STANDARDID,
    sgs.STORECODE AS STORECODE,
    sgs.SECTIONSDCID AS SECTIONSDCID,
    sgs.YEARID AS YEARID,
    sgs.STANDARDGRADE AS STANDARDGRADE,
    (select count(CCID) from validCC INNER JOIN STANDARDGRADESECTION sgs ON sgs.STUDENTSDCID = validCC.STUDENTSDCID and sgs.SECTIONSDCID = validCC.SECTIONID) as CC_OK,
    (select count(SECTIONID) from validCrsSection  INNER JOIN STANDARDGRADESECTION sgs ON  sgs.SECTIONSDCID = validCrsSect.SECTIONSDCID) AS CRS_OK,
    (select count(STANDARDID) from validStandard  INNER JOIN STANDARDGRADESECTION sgs ON  sgs.STANDARDID = validStandard.STANDARDID) AS STD_OK
FROM STANDARDGRADESECTION sgs

将“＆＃39; OK＆＃39; vGrades表中的列是因为最终的SELECT（未包含）经过并计算由检查过滤的某些分数的实例。

令人沮丧的是，学生表和部分表中都有两个ID（并且它们的数据不同）。因此，当我去链接所有内容时，一些表使用ID作为FK，其他表使用DCID作为FK;我必须拉一个额外的表来进行转换。以这种方式使连接变得更有趣。

每个单独的查询都可以自行运行，但我无法获得最终的select count（）来提取数据。我尝试将初始查询作为子查询嵌入，但我无法将studentid传递给它们，并且它会为每个学生运行该查询，而不是在开始时运行一次。

我当前的错误是：

Error starting at line : 13 in command -
    SECTIONS.DCID AS SECTIONSDCID,
Error report -
Unknown Command

然而，在它说出未知表并引用join语句的最后一行之前。所有表名都有效。想法？

Answer 1

我用一个简单的WHERE条件替换了INNER JOIN。这似乎有效。

Cookie: xyz=va;

Answer 2

我删除了validStandard末尾的迷路逗号，并将from validCrsSection替换为from validCrsSect（假设它是为了引用WITH条款而且没有＆＃39 ;另一个validCrsSection表）。我也猜测计数是要键入当前sgs行而不是整个表的计数。我这样说：

with validcc as
     ( select cc.id as ccid
            , cc.studentid
            , cc.sectionid
            , cc.termid
            , st.dcid as studentsdcid
       from   cc
              join students st on st.id = cc.studentid
       where  cc.termid in (2700, 2701)
       and    cc.schoolid = 406
     )
   , validcrssect as
     ( select s.id as sectionid
            , s.dcid as sectionsdcid
            , s.excludefromhonorroll as secthr
            , c.course_number
            , c.course_name
            , c.excludefromhonorroll  as crshr
       from   sections s
              join courses c
                   on  c.course_number = s.course_number
                   and c.schoolid = s.schoolid
       where  s.termid in (2700, 2701)
       and    s.schoolid = 406
       and    s.excludefromhonorroll = 0
       and    c.excludefromhonorroll = 0
     )
   , validstandard as
      ( select standardid
             , identifier
             , transientcourselist
        from   standard
        where  isactive = 1
        and    yearid = 27
        and    (   instr(standard.identifier, 'MHS.TS', 1, 1) > 0
                or standard.identifier in ('MHTC.TS.2','MHTC.TS.4') )
     )
select sgs.standardgradesectionid as sgsid
     , sgs.studentsdcid
     , sgs.standardid
     , sgs.storecode
     , sgs.sectionsdcid
     , sgs.yearid
     , sgs.standardgrade
     , ( select count(*) from validcc
         where  validcc.studentsdcid = sgs.studentsdcid
         and    validcc.sectionid = sgs.sectionsdcid ) as cc_ok
     , ( select count(*) from validcrssect
         where  validcrssect.sectionsdcid = sgs.sectionsdcid ) as crs_ok
     , ( select count(*) from validstandard
         where  validstandard.standardid = sgs.standardid ) as std_ok
from   standardgradesection sgs;

这适用于反向工程的六个表定义：

create table students
( id integer not null
, dcid integer );

create table cc
( id integer
, studentid integer
, sectionid integer
, termid integer
, schoolid integer );

create table courses
( course_number integer
, course_name varchar2(30)
, excludefromhonorroll integer
, schoolid integer );

create table sections
( id integer not null
, dcid integer
, excludefromhonorroll integer
, termid integer
, schoolid integer
, course_number integer );

create table standard
( standardid integer
, identifier varchar2(20)
, transientcourselist varchar2(50)
, isactive integer
, yearid integer );

create table standardgradesection
( standardgradesectionid integer
, studentsdcid integer
, standardid integer
, storecode integer
, sectionsdcid integer
, yearid integer
, standardgrade integer );

查找子查询中是否存在行

2 个答案: