我遇到与here所述完全相同的问题。
我正在尝试使用此Intent:
android.provider.ContactsContract.Intents.ATTACH_IMAGE
Starts an Activity that lets the user pick a contact to attach an image to.
听起来很合适,但很遗憾会产生ActivityNotFoundException
。
代码:
import android.provider.ContactsContract;
...
try {
Intent myIntent = new Intent();
myIntent.setAction(ContactsContract.Intents.ATTACH_IMAGE);
myIntent.setData(imageUri);
startActivity(myIntent);
} catch (ActivityNotFoundException anfe) {
Log.e("ImageContact",
"Firing Intent to set image as contact failed.", anfe);
showToast(this, "Firing Intent to set image as contact failed.");
}
我在上面的代码中找不到任何错误。 imageUri
对于以下代码完美运行是正确的:
代码:
try {
Intent myIntent = new Intent();
myIntent.setAction(Intent.ACTION_ATTACH_DATA);
myIntent.setData(imageUri);
startActivity(myIntent);
} catch (ActivityNotFoundException anfe) {
Log.e("ImageContact",
"Firing Intent to set image as contact failed.", anfe);
showToast(this, "Firing Intent to set image as contact failed.");
}
如链接中所述,这会在到达联系人之前生成另一个菜单。这是可以接受但不完美的。
答案 0 :(得分:1)
如果您已经知道可以使用的文件路径:
values.put(Images.Media.DISPLAY_NAME, fileName);
values.put(Images.Media.DATE_ADDED, currentTime);
values.put(Images.Media.MIME_TYPE, "image/jpeg");
values.put(Images.Media.ORIENTATION, 0);
values.put(Images.Media.DATA, filePath);
values.put(Images.Media.SIZE, size);
getContentResolver().insert(Images.Media.EXTERNAL_CONTENT_URI, values);
如果您已经拥有该文件,这样就无法打开位图流。
答案 1 :(得分:0)
我也有这个问题。通过使用从http://developer.android.com/guide/topics/providers/content-providers.html
获取的以下代码设置Uri,我获得了更多成功但是,选择联系人并裁剪图像后,仍未设置新的联系人图标?
// Save the name and description of an image in a ContentValues map.
ContentValues values = new ContentValues(3);
values.put(Media.DISPLAY_NAME, "road_trip_1");
values.put(Media.DESCRIPTION, "Day 1, trip to Los Angeles");
values.put(Media.MIME_TYPE, "image/jpeg");
// Add a new record without the bitmap, but with the values just set.
// insert() returns the URI of the new record.
Uri uri = getContentResolver().insert(Media.EXTERNAL_CONTENT_URI, values);
// Now get a handle to the file for that record, and save the data into it.
// Here, sourceBitmap is a Bitmap object representing the file to save to the database.
try {
OutputStream outStream = getContentResolver().openOutputStream(uri);
sourceBitmap.compress(Bitmap.CompressFormat.JPEG, 50, outStream);
outStream.close();
} catch (Exception e) {
Log.e(TAG, "exception while writing image", e);
}