Question

我的代码如下;

$stock_property_templates = StockPropertyTemplate::where('group_id' , 100)->where('type' , 'property')->get();

始终输出以下代码：此处

if($stock_property_templates) {
            echo "have Data";
        }else {
            echo "do not Have Data";
        }

此代码正在运行，但我不希望它以这种方式工作 - ＆gt; ＆＃34; []＆＃34;

if($stock_property_templates != "[]") {
            echo "have Data";
            return $stock_property_templates;
        }else {
            echo "do not Have Data";
        }

如何编写健康的代码？

Answer 1

使用isNotEmpty()方法检查集合是否为空：

if ($stock_property_templates->isNotEmpty())

或count()：

if (count($stock_property_templates))

或者：

if ($stock_property_templates->count())

Answer 2

您可以通过2种方式查看

方式

$stock_property_query = StockPropertyTemplate::where('group_id' , 100)->where('type' , 'property');
$stock_property_result = $stock_property_query->get();
if( $stock_property_query->count() == 0 ) {
  echo "do not Have Data";
} else {
  echo "Have Data";
}

方式二

$stock_property_result = StockPropertyTemplate::where('group_id' , 100)->where('type' , 'property')->get();
if(count($stock_property_result) == 0) {
  echo "do not Have Data";
} else {
  echo "Have Data";
}

Answer 3

检查数组empty()

if(!empty($stock_property_templates)) {
            echo "girdi";
            return $stock_property_templates;
        }else {
            return "girmedi";
        }

如何使用Laravel查询结果控件（if，else）？

3 个答案: