使用python中的递归在dfs中超出了最大递归深度

Question

我已经编写了一个python代码来解决使用python中的递归dfs的传教士和食人族问题。但是我一直收到这个错误：     RecursionError：超出最大递归深度

我不知道该怎么办，而且我已经坚持了很久。 任何帮助或建议都将为我节省生命。谢谢。 这是代码：

class State(object):
#left = 1
#right = 0 for boat
        def __init__(self, missionaries, cannibals, boat):
    self.missionaries = missionaries
    self.cannibals = cannibals
    self.boat = boat

#def __str__(self):
#    return "%s, %s %s %s" % (self.by_move, self.missionaries, self.cannibals, self.boat)

def is_valid(self):
    if self.missionaries < 0 or self.missionaries > 3:
        return False
    if self.cannibals < 0 or self.cannibals > 3:
        return False
    if self.boat > 1 or self.boat < 0:
        return False
    if self.missionaries < self.cannibals and self.missionaries > 0:
        return False
    # Check for the other side
    if self.missionaries > self.cannibals and self.missionaries < 3:
        return False

    return True

def is_goal(self):
    return self.missionaries == 0 and self.cannibals == 0 and self.boat == 0

def new_states(self):
    op = -1  # Subtract
    boat_move = "from left shore to right"
    if self.boat == 0:
        op = 1  # Add
        boat_move = "from right shore to left"

    for x in range(3):
        for y in range(3):
            by_move = "Move %s missionaries and %s cannibals %s" % (x, y, boat_move)
            new_state = State(self.missionaries + op * x, self.cannibals + op * y, self.boat + op * 1)
            if x + y >= 1 and x + y <= 2 and new_state.is_valid():
                yield new_state

class Node(object):
def __init__(self, parent, state, depth):
    self.parent = parent
    self.state = state
    self.depth = depth

def children(self):
    for state in self.state.new_states():
        yield Node(parent=self, state=state, depth=self.depth + 1)

def extract_solution(self):
    print
    "Extracting soln"
    solution = []
    node = self
    solution.append(node)
    while node.parent is not None:
        solution.append(node.parent)
        node = node.parent
    solution.reverse()
    return solution

def dfs(root,visited,sol = None):
if root in visited:
    return
if root is None:
    return
visited.append(root)
if root.state.is_goal():
    sol = root
    return

for child in root.children():
    if child not in visited:
        dfs(child,visited,sol)

def main():
    initial_state = State(3,3,1)
    root = Node(parent = None, state = initial_state,depth = 0)
    visited = []
    sol = Node(parent = None, state = initial_state,depth = 0)
    dfs(root,visited,sol)
    ans = sol.extract_solution()
    print(ans)


if __name__ == '__main__':
    main()

Answer 1

有两个问题：

1：您的列表已访问过＆＃39;没有正确跟踪所有州。这可以通过访问一个全局变量（通过将其置于def main（）之前，如最终解决方案中所做的那样）轻松修复。

2：该计划正在寻找无法帮助的可能性（例如：来回带来同一个人），这个

if root in visited:
    return
if root is None:
    return

没有解决这个问题，因为它永远不会是同一个根对象（即使root.state.mission，canibals和boat是相同的值），所以我使用字典对象改变了这个： / p>

if root is None:
    return
state = str(root.state.missionaries) + ',' + str(root.state.cannibals) + ',' + str(root.state.boat)
if state in routes:
    if routes[state] < root.depth:
        return
    else:
        routes[state] = root.depth
else:
    routes[state] = root.depth
visited.append(root)

这导致以下代码（它返回一个答案，我不确定它是否正确，因为我不知道传教士和食人族的问题）

class State(object):
#left = 1
#right = 0 for boat
    def __init__(self, missionaries, cannibals, boat):
        self.missionaries = missionaries
        self.cannibals = cannibals
        self.boat = boat

    #def __str__(self):
    #    return "%s, %s %s %s" % (self.by_move, self.missionaries, self.cannibals, self.boat)

    def is_valid(self):
        if self.missionaries < 0 or self.missionaries > 3:
            return False
        if self.cannibals < 0 or self.cannibals > 3:
            return False
        if self.boat > 1 or self.boat < 0:
            return False
        if self.missionaries < self.cannibals and self.missionaries > 0:
            return False
        # Check for the other side
        if self.missionaries > self.cannibals and self.missionaries < 3:
            return False

        return True

    def is_goal(self):
        return self.missionaries == 0 and self.cannibals == 0 and self.boat == 0

    def new_states(self):
        op = -1  # Subtract
        boat_move = "from left shore to right"
        if self.boat == 0:
            op = 1  # Add
            boat_move = "from right shore to left"

        for x in range(3):
            for y in range(3):
                by_move = "Move %s missionaries and %s cannibals %s" % (x, y, boat_move)
                new_state = State(self.missionaries + op * x, self.cannibals + op * y, self.boat + op * 1)
                if x + y >= 1 and x + y <= 2 and new_state.is_valid():
                    yield new_state

class Node(object):
    def __init__(self, parent, state, depth):
        self.parent = parent
        self.state = state
        self.depth = depth

    def children(self):
        for state in self.state.new_states():
            yield Node(parent=self, state=state, depth=self.depth + 1)

    def extract_solution(self):
        print "Extracting soln"
        solution = []
        node = self
        solution.append(node)
        while node.parent is not None:
            solution.append(node.parent)
            node = node.parent
        solution.reverse()
        return solution

def dfs(root,sol = None):
    if root is None:
        return
    state = str(root.state.missionaries) + ',' + str(root.state.cannibals) + ',' + str(root.state.boat)
    if state in routes:
        if routes[state] < root.depth:
            return
        else:
            routes[state] = root.depth
    else:
        routes[state] = root.depth
    visited.append(root)

    if root.state.is_goal():
        sol = root
        return

    for child in root.children():
        if child not in visited:
            dfs(child,sol)

visited = []
routes = {}

def main():
    initial_state = State(3,3,1)
    root = Node(parent = None, state = initial_state,depth = 0)
    sol = Node(parent = None, state = initial_state,depth = 0)
    dfs(root,sol)
    ans = sol.extract_solution()
    print(ans)


if __name__ == '__main__':
    main()

PS。正如@PM 2Ring所说，下次：请在提问时修改你的缩进，这使得阅读代码更容易理解。您可以通过选择所有代码，向所有选定行添加选项卡然后复制它来完成此操作。在粘贴之前，请确保空行。 ：）