Question

以下是我的代码，我正在传递stateid，并且我正在从stateid中检索数据。

代码适用于第一次迭代，即对于stateid = 1，它返回一个结果，但是对于第二次迭代，即当state_id = 2时，它返回两个记录，即s_id = 1和2。

如何解决此问题并仅获取s_id = stateid的具体记录？

数据库结构是： -

s_id  base_formid           base_xpath
1          1        .//*[@id='collapse-text-dynamic-form-number-1']/div/fieldset/legend/span/a
2          2        .//*[@id='collapse-text-dynamic-form-number-1']/div/fieldset/legend/span/a



public static Map baseXpath(int stateid)
{
    Statement s2 = null;
    try {

        con=null;
        con = DriverManager.getConnection(conUrl, userName, password);
        s2 = con.createStatement();

        String query = "SELECT  base_formid,base_xpath FROM base_path where base_path.s_id = " + stateid;

         ResultSet rs2 = null;
     rs2 = s2.executeQuery(query);
    while (rs2.next()) {
        int basepath_id = rs2.getInt(1);
        String base_xpath = rs2.getString(2);

        basex_path.put(basepath_id, base_xpath);


    }
        con.close();
        return basex_path;

Answer 1

由于您要将参数传递给select查询，我建议您使用PreparedStatement而不是Statement。下面的代码可以帮助您实现所需的结果。

public static Map baseXpath(int stateid)
{
    PreparedStatement s2 = null;
    try {

        con=null;
        con = DriverManager.getConnection(conUrl, userName, password);

        String query = "SELECT  base_formid,base_xpath FROM base_path where    base_path.s_id = ?";
         s2 = con.prepareStatement(query);
         s2.setInt(1, stateid);
         ResultSet rs2 = null;
     rs2 = s2.executeQuery();
    while (rs2.next()) {
        int basepath_id = rs2.getInt(1);
        String base_xpath = rs2.getString(2);

        basex_path.put(basepath_id, base_xpath);


    }
        con.close();
        return basex_path;
    }

查询/代码未返回所需结果

1 个答案: