Question

我正在为学校创建一个密码重置器，我想检查一下，如果密码在文本文件的第一行内，那么它可以说＆＃34;好的，选择一个新密码＆＃34; ）

Newpass=""
Network=""
setpass=""
Newpass=""
password=""
def newpass():
    Network=open("Userandpass.txt")
    lines=Network.readlines()
    password=input("just to confirm it is you, re-enter your old password:")
    for i in range (3):
        if password in line:
             newpass=input("Okay, choose a new password ")
             Network.close()
             Network=open("Userandpass.txt","a")
             if len(newpass)>= 8 and newpass[0].isalnum()==True and newpass[0].isupper()==True:
                print('password change successful')
                Network.write("New Password  : " + newpass )
                Network.close()
                break
             else:
                print("password did not match requirements, try again ")
        else:
            print("error")
            break
    print("3 tries up or else password updated")

Network=open("Userandpass.txt","w")
Network.write(input("What is your Username")+",")
Network.write(input("Password:")+ ",")
question=input("Do you want to change your password?")
if question=="yes":
    Network.close()
    newpass()
else:
     Network.close()
     print("Okay thank you.")

请帮忙！我一直在这里寻找，我无法找到解决方案

Answer 1

您可以尝试两件事：

lines=Network.read() # change here
password=input("just to confirm it is you, re-enter your old password:")
for i in range (3):
    if password == lines.split(",")[1]: # change here also

说明：

readlines的问题是o / p作为列表，其中read以字符串形式返回，这是在这里使用的更好的字母。
它作为单个字符串返回的第二件事，即名称和密码与,的组合形式。因此，如果您split，您将获得一个分隔值列表。然后，您只能从中password获取并检查输入在您的代码中，您只是检查input元素是否存在于整个字符串中，而不是检查它是否是相同的密码

Answer 2

你说你在学校需要这个，所以我认为这有点紧急：

我做的所有更改都是次要的，我评论了我做了什么以及为什么。

# no need to intialize these variables
#Newpass=""
#Network=""
#setpass=""
#Newpass=""
#password=""

def newpass():
    # the with open() construct takes care of closing the file for you and gives you a nice handle for working with the file object.
    with open("Userandpass.txt") as Network:
        # this reads all filecontents into a list and while doing so strips away any kind of whitespace.
        username,current_password=[x.strip() for x in Network.readlines()]
    for i in range (3):
        password=input("just to confirm it is you, re-enter your old password: ")
        if password == current_password:
            # communicate the requirements instead of letting potential users run into errors
            newpass=input("Okay, choose a new password (must be 8 chars or more, alphanumeric and have it's first letter capitalized.) ")
            if len(newpass)>= 8 and newpass.isalnum() and newpass[0].isupper():
                with open("Userandpass.txt","a") as Network:
                    print('password change successful')
                    Network.write("New Password  : " + newpass )
                return
            else:
                print("password did not match requirements, try again ")
        else:
            print("error")
            break
    print("3 tries up or else password updated")

with open("Userandpass.txt","w") as pwfile:
    # separate by newline instead of punctuation => personal preference
    pwfile.write(input("What is your Username? ")+"\n")
    pwfile.write(input("Password: ")+ "\n")

question=input("Do you want to change your password? (yes/no): ")

if question[0].lower() == 'y':
    newpass()
else:
    print("Okay thank you.")
    # properly terminate
    exit(0)

Answer 3

你错过了

中的's'

if password in line**s**:

也许问题来自那里。

如何查看我的密码变量是否在一行内，以便我的代码可以继续？

3 个答案: