Question

我正在尝试将我的sql程序销售报告拉到一个月的当前工作日和时间。

至于今天：February Day: 9 Time gone: 45.0%

as：time gone = workingday_of_the_month / workingdays_of_(particular)month.

有没有人有想法，如何拉工作日和节假日除外？

Answer 1

此功能允许您输入开始和结束日期，它将返回已用工作日数。我使用它的方法是添加一个英国公众假期的表格。然后，您可以将该函数用作SQL查询的一部分，以计算“时间消失”。

--Create table with each public holiday, including Y/N for Weekday.
CREATE TABLE [holidays](
    [DayName] [varchar](20) NOT NULL,
    [Date] [datetime] NOT NULL,
    [Weekday] [varchar](1) NOT NULL
    );

--2018 Bank Holidays
INSERT [holidays] ([DayName], [Date], [Weekday]) VALUES
    (N'New Years Day','2018-Jan-01','Y'),
    (N'Good Friday','2018-Mar-30','Y'),
    (N'Easter Monday','2018-APr-02','Y'),
    (N'Early May BH','2018-May-07','Y'),
    (N'Spring BH','2018-May-28','Y'),
    (N'Summer BH','2018-Aug-27','Y'),
    (N'Christmas Day','2018-Dec-25','Y'),
    (N'Boxing Day','2018-Dec-26','Y');

CREATE FUNCTION [WorkDayCount](
    @Startdate datetime,
    @EndDate datetime)
RETURNS INT
AS
BEGIN
DECLARE 
    @Holidays int,
    @WorkDays int

SELECT @Holidays = COUNT(distinct Date) FROM HOLIDAYS 
WHERE Date BETWEEN @StartDate AND @EndDate AND [Weekday]='Y'

SELECT @WorkDays = ((
    -- Days between start and end dates
    (DATEDIFF(dd, @StartDate, @EndDate))
    -- Minus the number of weekend days between start and end dates
    -(DATEDIFF(wk, @StartDate, @EndDate) * 2)
    -- Minus an extra day if starting on a Sunday
    -(CASE datepart(dw, @StartDate)+@@datefirst WHEN 8 THEN 1 ELSE 0 END) 
    -- Minus an extra day if ending on a saturday
    -(CASE datepart(dw, @EndDate)+@@datefirst WHEN 7 THEN 1 WHEN 14 THEN 1 ELSE 0 END))
    -- Minus Holiday Days
    - @Holidays)
RETURN @WorkDays
END

SQL如何获取一个月的工作日（不包括所有假期）

1 个答案: