我试图用fft从声波中获取频率。我找到了一种FFT方法,但是我无法理解它希望我输入什么,如何从中获取信息,以及如何使用我从中获得的信息。我已经尝试将缓冲区索引处的值输入为y,缓冲区位置为x,但是我得到了奇怪的结果。 int m似乎与样本有关,但我不知道如何选择我想要输入的内容。但它会影响存储到x和y中的多少。幸运的是,dir很容易理解,它基本上就像你是否向前推进FFT一样。
public static void FFT(short dir, int m, double[] x, double[] y)
{
int n, i, i1, j, k, i2, l, l1, l2;
double c1, c2, tx, ty, t1, t2, u1, u2, z;
// Calculate the number of points
n = 1;
for (i = 0; i < m; i++)
n *= 2;
// Do the bit reversal
i2 = n >> 1;
j = 0;
for (i = 0; i < n - 1; i++)
{
if (i < j)
{
tx = x[i];
ty = y[i];
x[i] = x[j];
y[i] = y[j];
x[j] = tx;
y[j] = ty;
}
k = i2;
while (k <= j)
{
j -= k;
k >>= 1;
}
j += k;
}
// Compute the FFT
c1 = -1.0;
c2 = 0.0;
l2 = 1;
for (l = 0; l < m; l++)
{
l1 = l2;
l2 <<= 1;
u1 = 1.0;
u2 = 0.0;
for (j = 0; j < l1; j++)
{
for (i = j; i < n; i += l2)
{
i1 = i + l1;
t1 = u1 * x[i1] - u2 * y[i1];
t2 = u1 * y[i1] + u2 * x[i1];
x[i1] = x[i] - t1;
y[i1] = y[i] - t2;
x[i] += t1;
y[i] += t2;
}
z = u1 * c1 - u2 * c2;
u2 = u1 * c2 + u2 * c1;
u1 = z;
}
c2 = Math.Sqrt((1.0 - c1) / 2.0);
if (dir == 1)
c2 = -c2;
c1 = Math.Sqrt((1.0 + c1) / 2.0);
}
// Scaling for forward transform
if (dir == 1)
{
for (i = 0; i < n; i++)
{
x[i] /= n;
y[i] /= n;
}
}
答案 0 :(得分:1)
我的猜测是:
m: Log2 of the data length
x: real part of input data
y: imaginary part of input data (array of 0s if the signal consists of only real numbers)
我没有测试过,请告诉我它是否有效。