Question

当我运行下面的decorate_keyword（）函数时，我遇到了两个我正在尝试解决的错误。第一个似乎最容易解决。我得到......

警告：DOMXPath :: query（） [domxpath.query]：表达式无效在 C：\ Xampplite文件\ htdocs中\测试网站\可湿性粉剂内容\插件\为myplugin \的index.php 第48行

它指向函数中的$ nodes行，并且当它包含空格时显然源于$ keyword变量。 $ keyword =“test”不会抛出错误。我需要更改什么才能克服此错误？

function rseo_decorate_keyword($postarray) {
    $keyword = "test";
    $content = $postarray['post_content'];
    /* 
     even though I can echo $content and get a string, 
     I'm getting error: Empty string supplied in loadHTML() when I use this. 
     so, I have to explicity set it to a string as below to test.
   */
    $content = "this is a test phrase";
    $d = new DOMDocument();
    $d->loadHTML($content);
    $x = new DOMXpath($d);
    $nodes = $x->query("//text()[contains(.,$keyword) and not(ancestor::h1) and not(ancestor::h2) and not(ancestor::h3) and not(ancestor::h4) and not(ancestor::h5) and not(ancestor::h6)]");
    if ($nodes && $nodes->length) {
        $node = $nodes->item(0);
        // Split just before the keyword
        $keynode = $node->splitText(strpos($node->textContent, $keyword));
        // Split after the keyword
        $node->nextSibling->splitText(strlen($keyword));
        // Replace keyword with <b>keyword</b>
        $replacement = $d->createElement('b', $keynode->textContent);
        $keynode->parentNode->replaceChild($replacement, $keynode);
    }
     $postarray['post_content'] = $d;
return $postarray;
}

Answer 1

如果contains XPath函数包含各种字符，例如;&,，则它应该在引号中包含第二个参数。空间就是其中之一。

$nodes = $x->query("//text()[contains(.,'$keyword') and not(ancestor::h1) and not(ancestor::h2) and not(ancestor::h3) and not(ancestor::h4) and not(ancestor::h5) and not(ancestor::h6)]");

对于mysql_real_escape_string错误，由于某种原因，正在传递对象而不是字符串。我不熟悉Wordpress内部：你应该用适当的标签提出一个单独的问题。

使用DOMDocument进行html解析帮助解决2个错误

1 个答案: