鉴于这是一个nuxt链接:
<nuxt-link :to="generateCategoryLink($store.state.locale, category.id)" exact :class="{active: isCategoryActive(category.id)}">
// Calls this method to get the link
generateCategoryLink(locale, categoryID) {
let query = this.$nuxt.$route.query;
if (this.isCategoryActive(categoryID)) {
query.categories = this.getQueriedCategories(categoryID);
} else {
query.categories = this.getQueriedCategories() + (this.getQueriedCategories() ? "," : "") + categoryID;
}
return {path: '/' + locale + '/projects/1', query};
}
如果我使用此代码,该方法始终返回旧params的链接。将此更改为:
return {path: '/' + locale + '/projects/1', query: { categories: query.categories}};
有效,但因为我想要包含所有其他旧的参数(仅修改query.categories),这不是一个选项。
答案 0 :(得分:0)
这应该可以解决问题:
return {path: '/' + locale + '/projects/1', query: { ...query, categories: query.categories}};