我使用Carbon
在2个日期之间使用diff()函数$fecha1 = \Carbon\Carbon::parse('2017-12-05');
$fecha2 = \Carbon\Carbon::parse('2018-02-09');
$resta = $fecha2->diff($fecha1)->format('%y years, %m months and %d days');
结果
0年,2个月和4天
我想要这个结果
2个月和4天
因为年数是0 任何解决方案?
答案 0 :(得分:5)
使用diffInYears()
:
$format = $fecha2->diffInYears($fecha1) > 0 ? '%y years, %m months and %d days' : '%m months and %d days';
$resta = $fecha2->diff($fecha1)->format($format);
答案 1 :(得分:0)
更通用的解决方案。它将分别存储每种类型的差异(年,月,日),并且只有在它与0不同时才显示。
<?php
$fecha1 = \Carbon\Carbon::parse('2017-12-05');
$fecha2 = \Carbon\Carbon::parse('2018-02-09');
$diff = $fecha2->diff($fecha1);
$diffByType = [
"years" => $diff->format("%y"),
"months" => $diff->format("%m"),
"days" => $diff->format("%d"),
];
$output = [];
foreach ($diffByType as $type => $diff) {
if ($diff != 0) {
$output[] = $diff." ".$type;
}
}
echo implode(", ", $output);
示例输出:
2017-12-05和2018-12-09:1年4天
2017-12-05和2018-02-05:2个月
答案 2 :(得分:0)
您应该考虑当您的差异包括0天或数月时会发生什么。你必须承担很多可能性:
function getDifference(string $start, string $end): string
{
$formatted = (new DateTime($end))->diff(new DateTime($start))->format('%y years, %m months, %d days');
$nonZeros = preg_replace('/(?<!\d)0\s?[a-z]*,\s?/i', '', $formatted);
$commaPosition = strrpos($nonZeros, ',');
return $commaPosition ? substr_replace($nonZeros, ' and', $commaPosition, 1) : $nonZeros;
}
var_dump(
getDifference('2017-12-05', '2018-02-09'),
getDifference('2017-12-05', '2017-12-09'),
getDifference('2013-12-05', '2017-12-09'),
getDifference('2013-12-05', '2017-10-09')
);
结果将是
string(19) "2 months and 4 days"
string(6) "4 days"
string(18) "4 years and 4 days"
string(29) "3 years, 10 months and 4 days"