Question

我需要匿名化IPv4和IPv6地址，因此我编写了这个粗略的解决方案：

if (strlen($_SERVER['REMOTE_ADDR']) <= 15) {  // Sorry: 15 NOT 12
    echo htmlentities(substr_replace($_SERVER['REMOTE_ADDR'], 'XXX', -3), ENT_QUOTES);
} else {
    echo htmlentities(substr_replace($_SERVER['REMOTE_ADDR'], 'XXXX:XXXX', -9), ENT_QUOTES);
}

它适用于全长IPv4和IPv6地址，如

207.142.131.005

2001：0db8：0000：08d3：0000：8a2e：0070：7344

但不是缩写地址，如

207.142.131.5

2001：0db8 :: 8d3 :: 8a2e：7：7344

我想知道是否有一个优雅的preg_replace解决方案和一些正则表达式魔法？

Answer 1

无需任何条件。您可以为单个preg_replace()调用处理编写两个模式和两个替换项。

代码：（Demo）

$tests=[
    "207.142.131.005",
    "2001:0db8:0000:08d3:0000:8a2e:0070:7344",
    "2001:0db8:0000:08d3:0000:8a2e:0070:734a",
    "207.142.131.5",
    "2001:0db8::8d3::8a2e:7:7344",
    "::1",
    "127.0.0.1"
];

$tests=preg_replace(['/\.\d*$/','/[\da-f]*:[\da-f]*$/'],['.XXX','XXXX:XXXX'],$tests);

var_export($tests);

输出：

array (
  0 => '207.142.131.XXX',
  1 => '2001:0db8:0000:08d3:0000:8a2e:XXXX:XXXX',
  2 => '2001:0db8:0000:08d3:0000:8a2e:XXXX:XXXX',
  3 => '207.142.131.XXX',
  4 => '2001:0db8::8d3::8a2e:XXXX:XXXX',
  5 => ':XXXX:XXXX',
  6 => '127.0.0.XXX',
)

模式说明：

的IPv4：

/         #Pattern delimiter
\.        #Match dot literally
\d*       #Match zero or more digits
$         #Match the end of the string
/         #Pattern delimiter

的IPv6

/         #Pattern delimiter
[\da-f]*  #Match zero or more digits or a b c d e f
:         #Match colon
[\da-f]*  #Match zero or more digits or a b c d e f
$         #Match the end of the string
/         #Pattern delimiter

Answer 2

不使用正则表达式，您可以相应地.或:进行爆炸并替换最后两个部分：

<?php
function anonIp($ip)
{
    if (strpos($ip, ".") !== false) { // detect IP type by dots instead of length
        $pieces = explode(".", $ip);
        $nPieces = count($pieces);
        $pieces[$nPieces - 1] = $pieces[$nPieces - 2] = "XXX";
        return implode(".", $pieces);
    } else {
        $pieces = explode(":", $ip);
        $nPieces = count($pieces);
        $pieces[$nPieces - 1] = $pieces[$nPieces - 2] = "XXXX";
        return implode(":", $pieces);
    }
}
var_dump(anonIp("207.142.131.005")); // 207.142.XXX.XXX
var_dump(anonIp("2001:0db8:0000:08d3:0000:8a2e:0070:7344")); // 2001:0db8:0000:08d3:0000:8a2e:XXXX:XXXX
var_dump(anonIp("207.142.131.5")); // 207.142.XXX.XXX
var_dump(anonIp("2001:0db8::8d3::8a2e:7:7344")); // 2001:0db8::8d3::8a2e:XXXX:XXXX
var_dump(anonIp("::1")); // :XXXX:XXXX
var_dump(anonIp("127.0.0.1")); // 127.0.XXX.XXX

Demo

虽然我确定有一些不明显（或没有那么多）的情况会破坏，所以一定要先给它一个彻底的测试。

Answer 3

您可以尝试：

$string = $_SERVER['REMOTE_ADDR'];
if (strlen($string) <= 12) {
    echo htmlentities(preg_replace('/(\d+\.\d+.\d+.)(\d+)/', "$1XXX",  $string), ENT_QUOTES);
} else {
    echo htmlentities(preg_replace('/((?:[0-9a-f]+:){6})(\w+:\w+)/', "$1XXXX:XXXX", $string), ENT_QUOTES);
}

Answer 4

正则表达式：[0-9]+$ and [0-9]*:[0-9]+$或\d+$和\d*:\d+$

详细说明：

$断言位于行尾的位置
[]匹配列表中的单个字符
+匹配一次且无限次
*零和无限次之间的匹配

PHP代码：

function mask($ip)
{
  if (strpos($ip, ".") == true) {
    print_r(preg_replace('~[0-9]+$~', 'XXX', $ip) . "\n");
  } else {
    print_r(preg_replace('~[0-9]*:[0-9]+$~', 'XXXX:XXXX', $ip) . "\n");
  }
}

输出：

207.142.131.XXX
207.142.131.XXX
2001:0db8:0000:08d3:0000:8a2e:XXXX:XXXX
2001:0db8::8d3::8a2e:XXXX:XXXX
:XXXX:XXXX

Code demo

使用PHP preg_replace匿名化IPv4和IPv6地址？

4 个答案: