Question

我有以下Dataframe

df1:
col1 col2 timestamp
0    4    1512712800000
1    6    1512712800000
2    4    1518510600000
3    8    1512712800000
4    9    1518510600000

我想像这样转换时间戳

datetime.fromtimestamp(int("1518485400000")/1000)

>>>>2018-02-13 02:30:00

并将其另存为数据框中的新列

所以看起来应该是这样的

df1:
col1 col2 timestamp       Date
0    4    1512712800000   2018-02-13 02:30:00
1    6    1512712800000   2018-02-13 04:30:00
2    4    1518510600000   2018-02-13 01:35:00
3    8    1512712800000   2018-02-13 08:30:00
4    9    1518510600000   2018-02-13 09:30:00

然后我试着以这种方式做到这一点

df1['Date'] = (datetime.fromtimestamp(int(df1.timestamp)/1000))

但是我收到编译错误。有什么问题，我该如何解决？

谢谢！

Answer 1

尝试这样的事情：

import pandas as pd
import datetime

df = pd.DataFrame({'col': [1,2], 'timestamp': ['1512712800000','1512713800000']})

print df

#    col      timestamp
# 0    1  1512712800000
# 1    2  1512713800000


convDate = lambda x: datetime.datetime.fromtimestamp(int(x)/1000)

df['date'] = df['timestamp'].apply(convDate)

print df

#    col      timestamp                date
# 0    1  1512712800000 2017-12-08 06:00:00
# 1    2  1512713800000 2017-12-08 06:16:40

Answer 2

这对你有用吗？

df1["Date"] = [datetime.fromtimestamp(int(x)/1000) for x in df1["timestamp"]]

我用以重新创建示例的完整代码：

import pandas as pd
from datetime import datetime

df1 = pd.DataFrame({"col1":[0,1,2,3,4],
                   "col2":[4,6,4,8,9],
                   "timestamp":["1512712800000","1512712800000","1518510600000","1512712800000","1518510600000"]})
df1["Date"] = [datetime.fromtimestamp(int(x)/1000) for x in df1["timestamp"]]
print (df1)

输出是这样的：

   col1  col2      timestamp                Date
0     0     4  1512712800000 2017-12-08 07:00:00
1     1     6  1512712800000 2017-12-08 07:00:00
2     2     4  1518510600000 2018-02-13 09:30:00
3     3     8  1512712800000 2017-12-08 07:00:00
4     4     9  1518510600000 2018-02-13 09:30:00

如何转换数据框中的时间戳

2 个答案: