Question

Laravel是否有某种功能允许我在Table-A中插入行，但必须插入Table-B，否则会失败？

Table-B表是多态关系。

Answer 1

正如@ C2486在答案中所说，你应该使用交易。但是，您无需使用try和catch。在Laravel文档的database transactions部分中，您可以看到以下示例：

DB::transaction(function () {
    DB::table('users')->update(['votes' => 1]);

    DB::table('posts')->delete();
});

此方法将自动为您提交，如果在执行期间发生异常，它也会自动为您回滚。

Answer 2

使用beginTransaction确保运行所有查询。

function sleep(ms) { return new Promise(resolve => setTimeout(resolve, ms));}

async function exec(){
     const u = await getCurrUser(action.w); //get current user login data from indexeddb io
     await sleep(2000);
     return u;
};

exec()
    .then(u => {
        console.log(u);
    })
    .catch(e => {
        // deal with the error -- you MUST always either handle
        // rejections or return the promise chain to something that will
    });

export function getCurrUser(window) {
    return new Promise((resolve, reject) => {
        // ...
        _req.onsuccess = function(event) {
            let cursor = event.target.result;
            //confirm in this line that user object does has some value
            if (cursor) {
                 resolve(Object.assign({}, cursor);
            } else {
                 reject(new Error(/*...*/));
            }
        };
    });
};

对于模特，您可以查看this answer

Laravel - 必须插入两个表中，否则会失败

2 个答案: