Mongoose发现({})没有返回任何东西

时间:2018-02-13 10:37:59

标签: node.js mongodb

我想从我的数据库本地分析我的用户,但出于某种原因,以下代码不记录任何内容,建议?

const mongoose = require('mongoose');
const mongoURIDEV = 'mongodb://MY-URI';
const MONGO = mongoURIDEV;

mongoose.connect(MONGO);
const schema = require('../schema/users');

async function main() {
const users = await schema.find({});
    console.log(users.length);
}

main().catch((e) => {
    console.log(e);
});

编辑:这是使用的架构:

const mongoose = require('mongoose');

const { Schema } = mongoose;

const usersSchema = new Schema({
  id: String,
  uid: String,
  gender: String,
  forward: String,
  keyword: String,
  placeType: String,
  profile_pic: String,
  referenceName: String,
  order_restaurant: String,
  order_people: String,
  order_time: String,
  order_timestamp: Object,
  order_email: String,
  order_phone: String,
  order_contact: []
}, { collection: 'Users' });

module.exports = mongoose.model('Users', usersSchema);

它与生产中使用的相同,它运作得很好

2 个答案:

答案 0 :(得分:0)

试试这个 .exec()返回承诺

async function main() {
const users = await schema.find({}).exec();
    console.log(users.length);
    return users;
}

main().then((data) => {
    console.log(data);
}).catch((e) => {
    console.log(e);
});

答案 1 :(得分:0)

你可以这样做,你错过了wirte exec()

async function main() { const users = await schema.find({}).exec(){ console.log(users.length); }