Question

我对查询确实有困难。

当前查询

SELECT 
min(ID),
Date, 
CASE WHEN (ID) = '111' then SUM(Column1) END AS [Outcome1],
CASE WHEN (ID) = '222' then SUM(Column1) END AS [Outcome2],
CASE WHEN (ID) = '333' then SUM(Column1) END AS [Outcome3],
CASE WHEN (ID) = '444' then SUM(Column1) END AS [Outcome4]
FROM Table1
GROUP BY ID, Date

结果产生

|  ID |     Date | Outcome1 | Outcome2 | Outcome3 | Outcome4 |
|-----|----------|----------|----------|----------|----------|
| 111 | 01/01/18 |       20 |   (null) |   (null) |   (null) |
| 222 | 01/01/18 |   (null) |       20 |   (null) |   (null) |
| 333 | 01/01/18 |   (null) |   (null) |       20 |   (null) |
| 444 | 01/01/18 |   (null) |   (null) |   (null) |       20 |

然而，我正在寻找的结果是

|  ID |     Date | Outcome1 | Outcome2 | Outcome3 | Outcome4 |
|-----|----------|----------|----------|----------|----------|
| 111 | 01/01/18 |       20 |       20 |       20 |       20 |

我已经尝试过分组，但最终结果只是结果1在80.但我正在寻找它与4结果列一起显示。

任何人都可以帮我吗？感谢

SQL小提琴 - http://sqlfiddle.com/#!18/9516c/2

Answer 1

在SUM声明

之上应用case汇总

SELECT 
min(ID),
Date, 
SUM(CASE WHEN (ID) = '111' then Column1 END) AS [Outcome1],
SUM(CASE WHEN (ID) = '222' then Column1 END) AS [Outcome2],
SUM(CASE WHEN (ID) = '333' then Column1 END) AS [Outcome3],
SUM(CASE WHEN (ID) = '444' then Column1 END) AS [Outcome4]
FROM Table1
GROUP BY Date

同时从ID

中删除group by

Case语句出现在同一行SQL Server上

1 个答案: