在我的项目数据库中显示产品表,其中一列名为' Name' 因此,此表格可以包含'产品A'和'产品a' 应该在简单的选择查询中选择这两种产品。
我创建了索引:
CREATE INDEX IDX_PRODUCT_NAME ON PRODUCTS(NAME)
然后运行SQL查询:
SELECT /*+ INDEX(PRODUCTS IDX_PRODUCT_NAME)*/ *
FROM PRODUCTS
WHERE NAME='Product_a'
我做错了什么?
P.S。我知道有关更改会话标志的变体:
NLS_COMP=ANSI;
NLS_SORT=BINARY_CI;
但对于我有趣的变体没有更改数据库设置,它可能吗?或者例如仅为我的查询更改此标志。
更新
William Robertson 帮我评论。
CREATE INDEX IDX_PRODUCT_NAME ON PRODUCTS(UPPER(NAME))
之后运行查询:
SELECT *
FROM PRODUCTS
WHERE **UPPER**(NAME)='PRODUCT_A'
这个变种工作正常!
答案 0 :(得分:1)
一种方法是添加虚拟列:
create table demo_products
( id integer not null
, name varchar2(20)
, name_upper generated always as (upper(name)) );
create index demo_prod_upper_name_ix on demo_products(name_upper);
insert all
into demo_products (id, name) values (1, 'Prod A')
into demo_products (id, name) values (2, 'Prod a')
into demo_products (id, name) values (3, 'Prod B')
into demo_products (id, name) values (4, 'Prod b')
into demo_products (id, name) values (5, 'prod A')
into demo_products (id, name) values (6, 'Cheese')
into demo_products (id, name) values (7, 'Bananas')
select * from dual;
commit;
select count(*) from demo_products where name_upper = 'PROD A';
COUNT(*)
----------
3
Plan hash value: 4158816492
---------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 12 | 1 (0)| 00:00:01 |
| 1 | SORT AGGREGATE | | 1 | 12 | | |
|* 2 | INDEX RANGE SCAN| DEMO_PROD_UPPER_NAME_IX | 1 | 12 | 1 (0)| 00:00:01 |
---------------------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
2 - access("NAME_UPPER"='PROD A')