如何使用selenium在网页上选择子节点值

Question

这是我需要自动化的网页。复选框旁边的值是动态的。他们不是一成不变的。所以我想选择其中一个选项，当我点击搜索按钮时，将显示匹配的搜索结果。请帮忙。

Answer 1

我不是xpath的粉丝，但我认为这是你最好的选择。 请尝试以下方法：

收集手风琴下的所有跨度，如下所示：

List<WebElement> elements = driver.findElements(By.xpath("//div[@class='rms-accordion-content']/label/span")

然后遍历列表并使用数据绑定属性文本过滤掉所有元素：名称

希望这会有所帮助。 祝你好运！

Answer 2

driver.findElements（By.xpath（＆＃34; // DIV [@class =＆＃39;均方根手风琴式内容＆＃39;] /标签/跨度＆＃34））; Iterator i = elements.iterator（）; while（i.hasNext（））{WebElement row = i.next（）;的System.out.println（row.getText（））; }

这是我用的

Answer 3

下面的代码将显示所有复选框名称 注意：代码在C＃中

-- Create table with 93 strings of different lengths, plus one NULL string. Notice the only ASCII character not used is '!', so I will use it as a delimiter in LISTAGG.
create table strings as 
with letters as ( 
  select level num, 
  chr(ascii('!')+level) let 
  from dual 
  connect by level <= 126 - ascii('!') 
  union all 
  select 1, null from dual 
) 
select rpad(let,num,let) str from letters;

-- Note the use of LENGTHB to get the length in bytes, not characters.
  select str,   
  sum(lengthb(str)+1) over(order by str rows unbounded preceding) - 1 cumul_lengthb,   
  sum(lengthb(str)+1) over() - 1 total_lengthb,   
  count(*) over() num_values   
  from strings   
  where str is not null;

-- This statement implements the ON OVERFLOW TRUNCATE WITH COUNT option of LISTAGG in 12.2. If there is no overflow, the result is the same as a normal LISTAGG.
select listagg(str, '!') within group(order by str) || 
  case when max(total_lengthb) > 4000 then 
    '! ... (' || (max(num_values) - count(*)) || ')' 
  end str_list 
from ( 
  select str, 
  sum(lengthb(str)+1) over(order by str) - 1 cumul_lengthb, 
  sum(lengthb(str)+1) over() - 1 total_lengthb, 
  count(*) over() num_values 
  from strings 
  where str is not null 
) 
where total_lengthb <= 4000 
   or cumul_lengthb <= 4000 - length('! ... (' || num_values || ')');