我在MySQL表格中有以下格式的数据。 我想在MySql查询中将字符串值的计数作为不同的列获取,这意味着如果列具有3个不同的值,则在从数据库获取数据时将向结果中添加3列。
表:
task table id | task | ----|-----------| 1 | TASK1 | ----|-----------| 2 | TASK2 | ----|-----------| 3 | TASK3 | ----|-----------| priority table id | task_id | priority | ----|-----------|-----------| 1 | 1 | Low | ----|-----------|-----------| 2 | 1 | Medium | ----|-----------|-----------| 3 | 1 | High | ----|-----------|-----------| 4 | 1 | High | ----|-----------|-----------| 5 | 1 | Low | ----|-----------|-----------| 6 | 1 | Medium | ----|-----------|-----------| 7 | 1 | High | . . N
预期结果:
task |low_priority | medium_priority | high_priority -----|--------------|-----------------|-------------- TASK1| 2 | 2 | 3 -----|--------------|-----------------|--------------
现在,我正在尝试以下查询,但未找到预期的结果。
SELECT task, (CASE WHEN priority = 'low' THEN 1 ELSe 0 END ) AS 'low_priority',(CASE WHEN priority = 'medium' THEN 1 ELSE 0 END) AS 'medium_priority',(CASE WHEN priority = 'high' THEN 1 ELSE 0 END ) AS 'high_priority' FROM task LEFT JOIN priority ON priority.task_id = task.id GROUP BY task.id
答案 0 :(得分:1)
你可以这样做
SELECT task, SUM(CASE WHEN priority = 'Low' THEN 1 ELSE 0 END ) AS 'low_priority',
SUM(CASE WHEN priority = 'Medium' THEN 1 ELSE 0 END) AS 'medium_priority',
SUM(CASE WHEN priority = 'High' THEN 1 ELSE 0 END ) AS 'high_priority'
FROM task
LEFT JOIN priority ON priority.task_id = task.id GROUP BY task.id
HAVING SUM(CASE WHEN priority = 'Low' THEN 1 ELSE 0 END ) > 0 OR
SUM(CASE WHEN priority = 'Medium' THEN 1 ELSE 0 END ) > 0 OR
SUM(CASE WHEN priority = 'High' THEN 1 ELSE 0 END )
,结果将是
+-------+--------------+-----------------+---------------+ | task | low_priority | medium_priority | high_priority | +-------+--------------+-----------------+---------------+ | TASK1 | 2 | 2 | 3 | +-------+--------------+-----------------+---------------+ 1 row in set (0.00 sec)