我正在为分页结果编写存储过程,这个结果可以按某些值排序。我在select语句中确实有一个switch case,但因为它试图在rownum上执行orderby,所以它非常慢。
现在我正在尝试使用dyanmic sql在select之外构建查询,但我不知道我在做什么是可能的。
这是Oracle SQL Developer中的SQL:
create or replace PROCEDURE Sp_tsa_trainees_pagination (
schemeid IN INT,
searchval IN VARCHAR2,
pagesize IN INT DEFAULT 20,
currentpage IN INT DEFAULT 1,
--orderby IN VARCHAR2,
cursor_ OUT SYS_REFCURSOR)
AS
-- LOCAL VARIABLES
totalcount INT;
numberofpages INT;
startposition NUMBER;
endposition NUMBER;
orderby VARCHAR2(100) := 'surname asc' ;
dynamic_query VARCHAR(255) := 'row_number() over (order by t.SURNAME DESC, t.FORENAMES DESC) AS rnum';
BEGIN
-- Get total number of trainees in scheme
select COUNT(t.ORG_REGISTRATION_ID)
into totalcount FROM v_trainee t
where t.ORG_REGISTRATION_ID = schemeid
AND t.status = 'A' and LOWER(t.trainee_name) like '%' || LOWER(searchval) || '%';
-- calculate number of pages in the pagination by dividing total number of records by how many to display for each page
numberofpages := totalcount / pagesize;
-- get start position by multiplying number of records to display for each page by current page
startposition := pagesize *( currentpage-1);
-- add calculated start position by number of records to display to get end position
endposition := startposition + pagesize;
CASE orderby
WHEN 'surname desc' THEN dynamic_query := 'row_number() over (order by t.SURNAME DESC, t.FORENAMES DESC) AS rnum';
WHEN 'surname asc' THEN dynamic_query := 'row_number() over (order by t.SURNAME ASC, t.FORENAMES ASC) AS rnum';
END CASE;
OPEN cursor_ FOR
Select * from
(
SELECT
-- order by based on selection
dynamic_query rnum,
t.ORG_REGISTRATION_ID SearchId,
t.FORENAMES Forenames,
t.FORENAME Forename,
t.SURNAME Surname,
t.person_id PersonId,
t.trainee_name TraineeName,
t.STATUS Status,
t.IPD_ANNUAL_REVIEW_DATE AnnualReviewDate,
t.ANNUAL_REVIEW_STATUS AnnualReviewStatus,
t.payment_received PaymentRecieved,
t.TRAINEE_ID TraineeId,
t.IPD_SIGNUP_DATE IpdSignupDate,
t.START_DATE StartDate,
t.END_DATE EndDate,
t.LENGTH_ON_SCHEME LengthOnScheme,
t.EMPLOYEE_NUMBER EmploymentNumber,
t.SELECTED_LEVEL SelectedLevel,
t.SELECTED_LEVEL_DESCRIPTION SelectedLevelDescription,
t.ELIGIBLE_LEVEL EligibleLevel,
t.ELIGIBLE_LEVEL_DESCRIPTION EligibleLevelDescription,
sce.FORENAMES SceForenames,
sce.FORENAME SceForename,
sce.SURNAME SceSurname,
sce.mentor_name SceName,
sce.EMPLOYEE_NUMBER SceEmployeeNumber,
de.FORENAMES DeForenames,
de.FORENAME DeForename,
de.SURNAME DeSurname,
de.mentor_name DeName,
de.EMPLOYEE_NUMBER DeEmployeeNumber,
t.COMPLETED_ATTRIBUTE_LEVELS CompletedAttributeLevels,
t.ATTRIBUTE_LEVEL_COUNT AttributeLevelCount,
-- get percentage
CASE t.ATTRIBUTE_LEVEL_COUNT
WHEN 0 THEN 0
ELSE
COMPLETED_ATTRIBUTE_LEVELS / t.ATTRIBUTE_LEVEL_COUNT * 100
END percentage,
DECODE(F_ISTRAINEEGROUPMEMBER(t.ORG_REGISTRATION_ID, 'S', t.person_id),'Y','N','Y') WithoutTsaGroup,
orr.status SchemeStatus,
(select count(*) from TRAINING_GROUP_TRAINEE tgt where tgt.trainee_id = t.TRAINEE_ID) NUMBER_OF_GROUPS,
TotalCount
FROM v_trainee t
INNER JOIN org_registration orr ON t.ORG_REGISTRATION_ID = orr.id
LEFT OUTER JOIN v_mentor sce ON t.sce_id = sce.MENTOR_ID
LEFT OUTER JOIN v_mentor de ON t.de_id = de.MENTOR_ID
where t.ORG_REGISTRATION_ID = schemeid AND t.status = 'A'
and LOWER(t.trainee_name) like '%' || LOWER(searchval) || '%'
)
where rnum >= startposition and rnum <= endposition;
END;
我想将此变量与指定的sql一起使用:
dynamic_query rnum,
但是当我执行存储过程时,我收到了这个错误:
ORA-01722:无效的数字ORA-06512:at “db.SP_TSA_TRAINEES_PAGINATION”,第46行ORA-06512:第13行
所以基本上我的问题是我可以将一个SQL分配给VARCHAR2然后动态地在select语句中使用它。
答案 0 :(得分:0)
您可能需要动态SQL。例如:
create or replace procedure testDyn(n in number, C OUT SYS_REFCURSOR) is
vDynamicPart varchar2(1000);
vSQl varchar2(1000);
begin
--
if (n = 1) then
vDynamicPart := 'count(1)';
else
vDynamicPart := 'count(null)';
end if;
--
vSQl := 'select ' || vDynamicPart || ' from dual';
open C for vSQl;
end;
如果你打电话
declare
n1 number;
n2 number;
C1 SYS_REFCURSOR;
C2 SYS_REFCURSOR;
begin
testDyn(1, C1);
testDyn(2, C2);
fetch C1 into n1;
fetch C2 into n2;
dbms_output.put_line('n1: ' || n1);
dbms_output.put_line('n2: ' || n2);
end;
你得到:
n1: 1
n2: 0