Question

我已经为遗传算法编写了这段代码，该算法通过获取基因的随机int（质量，高度（指标）和腿力）来计算跳跃高度，然后用其他最佳表现随机再现自身存储在称为geneBoard的二维数组中的样本。现在我的问题;你认为写1000次相同值是不切实际的，所以我试着用这个：

float[,] geneBoard = Enumerable.Repeat(
    mass = GetMass(500, 1000), 
    height = GetHeight(150, 190), 
    force = GetForce(500, 3500), 
    fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)), 1000)
.ToArray();

而不是：

float[,] geneBoard = new float[4, 4]
        {
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) },
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) },
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) },
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) }
        };

如果我没有做足够好的工作解释，这是我的所有代码：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace Genetic_Algorithm
{
class Program
{
    static Random random = new Random(); // Getting a seed

    static void Main(string[] args)
    {


        float mass = GetMass(500, 1000);
        float height = GetHeight(150, 190);
        float force = GetForce(500, 3500);

        float fitnessScore = Convert.ToSingle( PhysicalTest(mass, height, force) );
        /*
        float[,] geneBoard = new float[4, 4]
        {
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) },
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) },
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) },
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) }
        };
        */
        float[,] geneBoard = Enumerable.Repeat(mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)), 1000).ToArray();

        float[] sortingAr = new float[] { geneBoard[0, 3], geneBoard[1, 3], geneBoard[2, 3], geneBoard[3, 3] };
        Array.Sort(sortingAr, (x, y) => y.CompareTo(x));

        Console.WriteLine(sortingAr[0]);
        Console.WriteLine(sortingAr[1]);
    }

    public static float GetMass(int min, int max)
    {
        int massGr = random.Next(min, max);
        float mass = massGr / 10;

        return mass;
    }

    public static float GetHeight(int min, int max)
    {
        int heightCm = random.Next(min, max);
        float height = heightCm / 10;

        return height;
    }

    public static float GetForce(int min, int max)
    {
        int force = random.Next(min, max);

        return force;
    }

    public static double PhysicalTest(float mass, float height, float force)
    {
        double d = force * 0.07; // gets distance of applied force
        double vi = Math.Sqrt( (force * d) / ( mass / 2 ) ); // calculats v initial
        double jumpHeight = (vi * vi) / (2 * 9.8); // calculates jumping height

        double fitnessScore = jumpHeight * 100;

        return fitnessScore;
    }
}

}

最后，我是初学者，所以任何其他建议都会有所帮助。

Answer 1

我认为Enumerable.Repeat不是你真正想要的。正如其名称所示，它只是一遍又一遍地重复相同的元素，而在您的情况下，我认为您想要的是创建1000个类似但不同的对象，代表你的基因。

在你的情况下，我想你之前创建的一个简单的for循环是绝对足够的。

Answer 2

你遇到的错误（没有重载方法'重复'需要5个参数。）是正常的，因为你正在以错误的方式使用Enumerable.Repeat。

Enumerable.Repeat需要2个参数：

要重复的元素
重复多少次

你给它5个参数，其中4个描述了AN元素。

解决方法是创建一个类来保存您的4个值：

public class Element
{
    public float Mass { get; set; }
    public float Height { get; set; }
    public float Force { get; set; }
    public double FitnessScore { get; set; }

    // Add constructor to take the 4 parameters
}

然后像这样使用它：

Element[] elements = Enumerable.Repeat(new Element(GetMass(500, 1000), GetHeight(150, 190), GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)), 1000).ToArray();

你可能想查看你的逻辑。因为这会给你100次SAME元素，我假设你想要1000个不同的objets具有相同的值。

C＃＆＃39; Enumerable.Repeat（）＆＃39;如何超载？

2 个答案: