Question

我一直在使用JSGrid来表示快速CRUD应用程序。来自MongoDB / Mongoose的数据可以很好地获取数据，但是当我在jsGrid上更新/删除时，它可以正常工作，但是重新加载时不会保存。基本上没有保存到MongoDB中。我尝试了一些事情并浏览了类似的帖子，但似乎无法弄清楚我做错了什么？ Javascript中的JSGrid代码

$(function() {
var filter =
 $("#jsGrid").jsGrid({
  height: "450px",
  width: "900px",
  filtering: true,
  inserting: true,
  editing: true,
  sorting: true,
  paging: true,
  autoload: true,
  pageSize: 10,
  pageButtonCount: 5,
  deleteConfirm: "Do you really want to delete client?",
  controller: {
      loadData: function(filter) {
          return $.ajax({
              type: "GET",
              url: "/projects",
              data: filter
            });
        },
      insertProject: function(filter) {
            return $.ajax({
                type: "POST",
                url: "/projects",
                data: Project
            });
        },
      updateproject: function(Project) {
          return $.ajax({
              type: "PUT",
              url: "/projects",
              data: Project
          });
      },
      deleteproject: function(Project) {
          return $.ajax({
              type: "DELETE",
              url: "/projects",
              data: Project
          });
      }
  },
  fields: [
      { name: "title", type: "text", width: 150 },
      { name: "location", type: "text", width: 50 },
      { name: "resources", type: "text", width: 200 },
      { type: "control" }
  ]

}）; }）;

Answer 1

您的控制器实施了错误的方法。正确的方法名称如下：

...
controller: {
    loadData: function(filter) {}, 
    insertItem: function(item) {}, 
    updateItem: function(item) {}, 
    deleteItem: function(item) {}
}

...

JsGrid发出数据从数据库加载但不保存更改以进行编辑/删除

1 个答案: