单击标签放置图像

时间:2018-02-12 06:48:09

标签: javascript jquery fabricjs

我在画布中有一个图像丢弃功能。如果用户点击图像,则将图像放在画布上。现在,我想点击标签做同样的事情。但由于标签没有naturalWidth& naturalHeight,它不起作用。

对于以下HTML,如果用户点击< img />标记其工作,但不点击(添加产品图像或添加QR码)。

HTML

<ul class="dropdown-menu drop-bwn-icon image-parent" role="menu">
    <li class="img_holder">
        <img class="control-label image_drop_class image_drop drag_item canvas-img" data-value="http://localhost/lynkus/uploads/userprofile/image_n.png" data-type="image" width="30" data-width="100" src="http://localhost/lynkus/uploads/userprofile/image_n.png" data-image-name="image_1" draggable="true" alt="verified_image" data-action="image">
        <span class="images_title image_drop_class" data-action="span">Add Product Images</span>
    </li>

    <li class="img_holder">
        <img class="control-label image_drop_class image_drop drag_item" data-value="http://localhost/lynkus/uploads/userprofile/qr-code.png" data-type="image" width="30" data-width="260" src="http://localhost/lynkus/uploads/userprofile/qr-code.png" data-image-name="qr_code" draggable="true" alt="verified_image" data-action="image">

        <span class="images_title image_drop_class" data-action="span">Add QR Code</span>
    </li>                               
</ul>

JQuery的

/* On click place image on canvas */
    $('.image_drop_class').click(function(){
        var obj = this;//document.querySelector('.image_drop');
        if($(obj).attr('data-action')=='span') // Owverwrite the object
        {
            var obj = $(this).parent().find('img:first');
        }
        var t_width = $(obj).attr('data-width');
        var setImageWidth = t_width;
        var setImageHeight = 100;
        var image_url = $(obj).attr('data-value');
        var image_id = $(obj).attr('data-image-name');
        var new_image = new fabric.Image(obj, {
            width: obj.naturalWidth,
            height: obj.naturalHeight,
            scaleX: setImageWidth/obj.naturalWidth,        
            scaleY: setImageHeight/obj.naturalHeight,
            left: 50,
            top: 50,
            id: image_id
        });
        console.log(new_image);
        canvas.add(new_image);
        canvas.renderAll();
    });

控制台输出

点击标签

  

klass {filters:Array(0),width:undefined,dirty:true,height:undefined,scaleX:NaN,...}

点击图片:

  

klass {filters:Array(0),width:100,dirty:true,height:100,scaleX:1,...}

1 个答案:

答案 0 :(得分:1)

问题是,当点击的元素是img时,obj将是Node,但当点击的元素是span时,它将是一个jQuery对象

你必须做这样的事情,所以你在两种情况下都使用相同类型的对象:

if($(obj).attr('data-action')=='span'){
    var obj = $(this).parent().find('img').get(0);
}