Question

我想弄清楚将delete pointer语句放在下面的程序中的哪个位置。我想清除pointer指向的内存空间，以避免内存泄漏。似乎无论我把它放在哪里，我都会收到错误声明：

main(8282,0x7fff95d823c0) malloc: *** error for object 0x7fff582d3960: pointer being freed was not allocated
*** set a breakpoint in malloc_error_break to debug

我不知道如何解决这个问题。任何帮助表示赞赏。

完整代码：

#include <iostream>
#include <vector>
using namespace std;

int main() {

    //initialize vector
    vector<int> historyValues;

    //initialize pointer and int variable
    int *pointer;
    pointer = new int;
    pointer = 0;
    int currentValue;

    //make pointer point to the address of currentValue
    pointer = &currentValue;

    //increment pointer by 1 for a total of 10 times.
    //since pointer is pointing at currentValue, currentValue should change also.
    //push back the current value of currentValue into the vector.

    for (int i = 0; i < 10; i++) {

        *pointer += 1;
        historyValues.push_back(currentValue);
    }

    //print final results
    cout << "currentValue: " << currentValue << endl;
    cout << "*pointer: " << *pointer << endl;

    cout << "History of integers stored in currentValue: ";

    for (int i = 0; i < historyValues.size(); i++) {

        cout << historyValues[i] << " ";
    }

    cout << endl;
    cout << "Program finished" << endl;

    return 0;
}

Answer 1

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改变的结果是：

delete pointer

但是，您也可以删除所有这三行，然后从pointer = new int; delete pointer; pointer = 0;开始，因为您的代码从不使用动态分配的pointer = &currentValue;。

另外，你的评论＆＃34;增加指针＆＃34;是不正确的。您正在递增指针的目标，而不是指针。

在哪里放置动态变量的运算符

1 个答案: