Question

给出以下对象数组：

[{
"JobPosition": [
    {
    "node": {
        "jobTitle": "Front end",
        "jobLocation": "LOCATION: London",
        "jobTest": {
        "id": "c3FDAuPSTfqIkIUi6qcOmqS__us"
        }
    }
    },
    {
    "node": {
        "jobTitle": "Back end developer",
        "jobLocation": "LOCATION: Milan ",
        "jobTest": {
        "id": "c3FDAuPSTfqIkIUi6qcOmqS___it"
        }
    }
    },
    {
    "node": {
        "jobTitle": "Android Developer",
        "jobLocation": "LOCATION: London",
        "jobTest": {
        "id": "c3FDAuPSTfqIkIUi6qcOmqS___de"
        }
    }
    }
]},
{
"JobsPage": [
    {
        "node": {
        "id": "c3FDAuPSTfqIkIUi6qcOmqS__us",
        "pageName": "Job",
        "seoTitle": "Jobs",
        "seoDescription": "Lorem Ipsum",
        "seoKeywords": "Lorem Ipsum, Lorem Ipsum, Lorem Ipsum",
        }
    },
    {
        "node": {
        "id": "c3FDAuPSTfqIkIUi6qcOmqS___it",
        "pageName": "Job",
        "seoTitle": "Work with us",
        "seoDescription": "Lorem Ipsum",
        "seoKeywords": "Lorem Ipsum, Lorem Ipsum, Lorem Ipsum",
        }
    },
    {
        "node": {
        "id": "c3FDAuPSTfqIkIUi6qcOmqS___de",
        "pageName": "Job",
        "seoTitle": "Jobs",
        "seoDescription": "Lorem Ipsum",
        "seoKeywords": "Lorem Ipsum, Lorem Ipsum, Lorem Ipsum",
        }
    }]
}]

我需要加入具有相同ID的条目并添加该语言的密钥，以实现此数据结构：

[{
    "us": [{
            "node": {
                "id": "c3FDAuPSTfqIkIUi6qcOmqS__us",
                "pageName": "Job",
                "seoTitle": "Jobs",
                "seoDescription": "Lorem Ipsum",
                "seoKeywords": "Lorem Ipsum, Lorem Ipsum, Lorem Ipsum",
            }
        },
        {
            "node": {
                "jobTitle": "iOS Mobile Developer",
                "jobLocation": "LOCATION: MILANO (IT)",
                "jobTest": {
                    "id": "c3FDAuPSTfqIkIUi6qcOmqS__us"
                }
            }
        }
    ]
}, {
    "it": [{
            "node": {
                "id": "c3FDAuPSTfqIkIUi6qcOmqS___it",
                "pageName": "Job",
                "seoTitle": "Lavora con noi",
                "seoDescription": "Lorem Ipsum",
                "seoKeywords": "Lorem Ipsum, Lorem Ipsum, Lorem Ipsum",
            }
        },
        {
            "node": {
                "jobTitle": "Front End",
                "jobLocation": "LOCATION: MILANO (IT)",
                "jobTest": {
                    "id": "c3FDAuPSTfqIkIUi6qcOmqS___it"
                }
            }
        }
    ]
}, {
    "de": [{
            "node": {
                "id": "c3FDAuPSTfqIkIUi6qcOmqS___de",
                "pageName": "Job",
                "seoTitle": "Lavora con noi",
                "seoDescription": "Lorem Ipsum",
                "seoKeywords": "Lorem Ipsum, Lorem Ipsum, Lorem Ipsum",
            }
        },
        {
            "node": {
                "jobTitle": "Back end developer",
                "jobLocation": "LOCATION: Milan",
                "jobTest": {
                    "id": "c3FDAuPSTfqIkIUi6qcOmqS___de"
                }
            }
        }
    ]
}]

我只设法加入一个对象中的所有内容，任何想法如何在javascript中完成此操作？也许filter和reduce方法可能会有所帮助，但我对它很新。感谢

Answer 1

Array.reduce() + Array.map()解决方案：

var data = [{ "JobPosition": [ { "node": { "jobTitle": "iOS Mobile Developer", "jobLocation": "LOCATION: MILANO (IT)", "jobTest": { "id": "c3FDAuPSTfqIkIUi6qcOmqS__us" } } }, { "node": { "jobTitle": "Android Mobile Developer - IT", "jobLocation": "LOCATION: MILANO (IT)", "jobTest": { "id": "c3FDAuPSTfqIkIUi6qcOmqS___it" } } }, { "node": { "jobTitle": "Android Mobile Developer - DE", "jobLocation": "LOCATION: MILANO (IT)", "jobTest": { "id": "c3FDAuPSTfqIkIUi6qcOmqS___de" } } } ]}, 
            { "JobsPage": [ { "node": { "id": "c3FDAuPSTfqIkIUi6qcOmqS__us", "pageName": "Job", "seoTitle": "Jobs", "seoDescription": "Lorem Ipsum", "seoKeywords": "Lorem Ipsum, Lorem Ipsum, Lorem Ipsum", } }, { "node": { "id": "c3FDAuPSTfqIkIUi6qcOmqS___it", "pageName": "Job", "seoTitle": "Lavora con noi", "seoDescription": "Lorem Ipsum", "seoKeywords": "Lorem Ipsum, Lorem Ipsum, Lorem Ipsum", } }, { "node": { "id": "c3FDAuPSTfqIkIUi6qcOmqS___de", "pageName": "Job", "seoTitle": "Jobs", "seoDescription": "Lorem Ipsum", "seoKeywords": "Lorem Ipsum, Lorem Ipsum, Lorem Ipsum", } }] }
],
groups = data[0].JobPosition.concat(data[1].JobsPage).reduce(function(r, o){
    var cc = (o.node.id || o.node.jobTest.id).substr(-2);  // extracting country code
    (r[cc])? r[cc].push(o) : r[cc] = [o];
    return r;
}, {}),

result = Object.keys(groups).map(function(k){
    var o = {};
    o[k] = groups[k];
    return o;
});

console.log(result);

Answer 2

使用map和filter，我添加了一个JSON.stringify来帮助您更好地查看结果：

import 'rxjs/add/observable/throw';

使用对象数组的相同ID连接条目

2 个答案: