Question

所以基本上我已经宣布了所有内容，但不知怎的，它们仍未能作为一种类型被解析。有任何想法吗？ JAVA screenshot

int main() {
        int pid, stat_loc;
        printf("\nmy pid = %d\n", getpid());
        pid = fork();

        if (pid == -1) {
                perror("error in fork");
                return 0;
        }
        else if (pid ==0 ) {
                printf("\nI am the child process, my pid = %d\n\n", getpid());
                sleep(5);
                exit(0);/* sending child status */
        }
        else {
                int status = 0;
                int ret = wait(&status);/* wait() returns pid of the child for which its waiting */
                printf("\nThe %d is done\n\n", ret);
                printf("\nI am the parent process, my pid = %d\n\n", getpid());  
        }
        printf("\nThe %d is done\n\n", getpid());/* getpid() returns pid of the process */
        return 0;
}

Answer 1

在声明之后，你不能引用一个对象，除非它是一个字段。尝试将您的声明移动到您的动作监听器：

from Foundation import NSAppleScript textOfMyScript = """ tell application "SpeechRecognitionServer" set theResponse to listen for {"good", "bad", "weather"} end tell """ myScript = NSAppleScript.initWithSource_(NSAppleScript.alloc(), textOfMyScript) results, err = myScript.executeAndReturnError_(None) myWord = results.stringValue() if myWord == "good": print ("OK")

您可能还想查看Oracle Creating Objects的教程和Using Objects。如果您不熟悉字段的工作原理，那么您会发现另一个非常方便的教程：Declaring Member Variables

Jbutton无法解决

1 个答案: