Question

只是想知道是否有人可以帮我解决一些问题，我正在解析json数据。我将从JSON的spinet开始，我将不包括所有内容（JSON也有效）：

"X_bizCardServiceLinks": [
    {
        "name": "blogs",
        "js_eval": "generalrs.label_personcard_blogslink",
        "href": "https:\/\/dc3-epag-03.tm-gnet.com\/blogs\/roller-ui\/blog\/dbb8fac0-42e4-102e-9409-b38b9530f95e"
    },
    {
        "name": "quickr",
        "js_eval": "generalrs.label_personcard_quickrlink",
        "href": "https:\/\/dc3-epag-03.tm-gnet.com\/quickr\/allfiles\/people\/Jonathan.Popoola@trinitymirror.com"
    },
    {
        "name": "profiles",
        "js_eval": "generalrs.label_personcard_profilelink",
        "href": "https:\/\/dc3-epag-03.tm-gnet.com\/profiles\/html\/simpleSearch.do?searchFor=dbb8fac0-42e4-102e-9409-b38b9530f95e&searchBy=userid"
    },
    {
        "name": "activities",
        "js_eval": "generalrs.label_personcard_activitieslink",
        "href": "https:\/\/dc3-epag-03.tm-gnet.com\/activities\/service\/html\/mainpage#dashboard%2Cmyactivities%2Cuserid%3Ddbb8fac0-42e4-102e-9409-b38b9530f95e%2Cname%3DJonathan Popoola"
    },
    {
        "name": "dogear",
        "js_eval": "generalrs.label_personcard_dogearlink",
        "href": "https:\/\/dc3-epag-03.tm-gnet.com\/dogear\/html?userid=dbb8fac0-42e4-102e-9409-b38b9530f95e"
    },
    {
        "name": "communities",
        "js_eval": "generalrs.label_personcard_communitieslink",
        "href": "https:\/\/dc3-epag-03.tm-gnet.com\/communities\/service\/html\/allcommunities?userid=dbb8fac0-42e4-102e-9409-b38b9530f95e"
    },
    {
        "name": "wikis",
        "js_eval": "generalrs.label.personcard.wikislink",
        "href": "https:\/\/dc3-epag-03.tm-gnet.com\/wikis\/home\/search?uid=dbb8fac0-42e4-102e-9409-b38b9530f95e&name=Jonathan Popoola"
    },
    {
        "name": "files",
        "js_eval": "generalrs.label_personcard_fileslink",
        "href": "https:\/\/dc3-epag-03.tm-gnet.com\/files\/app\/person\/dbb8fac0-42e4-102e-9409-b38b9530f95e"
    }
],

我需要做的是访问“X_bizCardServiceLinks”的每个子元素并将名称和href存储到变量中 - 我能够返回所有单个子项但不能单独定位每个子项 - 我使用以下内容代码：

$.each(response.X_bizCardServiceLinks, function(){
            $.each(this, function(n, v){
                var random = n;
                var anotherRandom = v;
                console.log(v); 
                //$("#linkTable tr").append("<td><a href=\""+ this.href +"\">"+ this.name +"</a>");
            });

        });

响应是JSON但存储，任何帮助都将非常感谢提前，

Answer 1

$.each(response.X_bizCardServiceLinks, function(index, elem) {
    // elem.name
    // elem.href
});

'"X_bizCardServiceLinks": []'

无论如何看起来像无效的JSON。它应该包含在{ }：

中

'{"X_bizCardServiceLinks": []}'

Answer 2

您正在使用每个函数为每个元素调用回调函数。遗憾的是，您没有指定参数，该参数可用于访问回调函数中的单个元素。

所以而不是 $ .each（response.X_bizCardServiceLinks，function（）{ 你会用的 $ .each（response.X_bizCardServiceLinks，function（index，el）{ 然后可以使用el.name和el.href获取子元素。

请参阅http://api.jquery.com/each/

中每个函数的jQuery API

$.each(response.X_bizCardServiceLinks, function(index, el){
    $.each(this, function(n, v){
        $("#linkTable tr").append("<td><a href=\""+ el.href +"\">"+ el.name +"</a>");
    });
});

Answer 3

你太努力了

$.each(response.X_bizCardServiceLinks, function(){
    var name = this.name;
    var href = this.href;            
    console.log(name, href);
});

http://jsfiddle.net/F8XPM/

使用jQuery解析循环json的困惑

3 个答案: