Question

我最近与小型个人助理项目合作，现在我正面临这个问题/错误，我无法克服它。

这是我的代码的一部分：

    import os
import sys
from colorama import Fore, Back, Style
import random
from os import system

from src import commands
system("title Assistant")

actions = {
    "open":["pubg", "dota", "origins", "spotify", "dogs"],#"open":{["o"]:["pubg", "dota", "origins", "spotify", "dogs"]},
    "hue":["1"],
    "clear":"",
    "hiber":"",
    "shutdown":""
}

class MainClass:
    #
    logo1 = Fore.CYAN + """Not essential"""

    logo2 = Fore.CYAN + """Not essential"""

    errorcode = "Something went wrong :("

    def getCommand(self):
        cmd = input(Fore.MAGENTA + "Assistant > " + Fore.CYAN)
        print("cmd: " + cmd)
        self.checkCommand(cmd)

    def checkCommand(self, cmd):
        actions = commands.Commands().actions
        words = cmd.lower().split()
        print("Words: " + ' '.join(words))
        found = False

        ekasana = ""
        par = ""

        print("running if " + words[0] + str(words[0] == "q"))

#Here's the problem. After I imput 'clear', which clear's the screen and runs mainInterface(2.0, randomthing), this if does not work.
# Here's the output
# Not essentialv 2.0
#                By Dudecorn
# Assistant > q
# cmd: q
# Words: q
# running if qTrue
# self.errorcode
# clear
# ['clear']
# Assistant >

# Why is is that clear command staying there? I am so confused right now.
# Read line 68

        if words[0] == "q":
            quit()
            sys.exit()

        for word in words:
            word = ''.join(word)# Sorry about the mess
            print(word)
            # Check for action without parameters
            if word in actions and actions[word] == "" and found == False:
                try: # I'm pretty sure that this part of code is causing the problem
                    # If you remove try and except, and leave just lines 70 and 71, code works as line 58 if statement's value is true.
                    # This is in the another file -> getattr(commands.Commands, word)(self)
                    self.mainInterface(2.0, random.randint(1, 2))
                    break
                except:
                    print("self.errorcode")
                    print(word)
                    print(words)
            # Check for action that has parameters
            elif word in actions and not actions[word] == "" and found == False:
                ekasana = word
                found = True
            # Check for parameters
            elif not ekasana == "" and found == True:
                for n in actions[ekasana]:
                    if n == word:
                        par = word
                        try:
                             getattr(commands.Commands, ekasana)(self, par)
                        except:
                            print(self.errorcode)
            else:
                print("Command not found")
        self.getCommand()


    def mainInterface(self, v, logo):
        os.system('cls' if os.name == 'nt' else 'clear')
        if logo == 1:
            print(self.logo1+"v "+str(v)+"\n                                       By Dudecorn")
        else:
            print(self.logo2+"v "+str(v)+"\n               By Dudecorn")
        self.getCommand()

这是主文件

import test
import random


def main():
    m = test.MainClass()
    m.mainInterface(2.0, random.randint(1,2))

main()

因此，当您运行代码并首先输入'clear'然后q时if语句将不会执行。我想知道为什么。我还注意到，如果你删除try和除了循环之后的第一个if语句，代码完美地工作。我可以删除它们，但它不会回答我的问题，为什么代码不能正常工作。另外，从文件中删除try和except不会对第一个if语句的执行方式产生任何影响，因为它会在代码中稍后出现。

抱歉英语不好，因为它不是我的主要语言，谢谢你的答案。我也想为代码中的那个巨大的混乱道歉。

Answer 1

我不确定这是否是您正在寻找的答案，但检查可能会有用。

从下面的代码

def main():
    m = test.MainClass()
    m.mainInterface(2.0, random.randint(1,2))
main()

，我看到通过运行main()，您还可以运行m.mainInterface功能。

现在..你可能想检查一下：

方法mainInterface 最终会调用方法getCommand，最终会调用checkCommand，它将会遇到try块在for word in actions循环中，以及此try块内...再次调用 mainInterface ..因此此过程将不断重复。

Python尝试和除了bug（可能）

1 个答案: