我有一个xlsx文件(它是第一张)
Postcode Sales_Rep_ID Sales_Rep_Name Year Value
2121 456 Jane 2011 $84,219
2092 789 Ashish 2012 $28,322
2128 456 Janet 2013 $81,879
2073 123 John 2011 $44,491
如何获取名为年的列的特定值,其 Sales_Rep_Name 值为Janet?我被困在下面的代码中,无法想办法怎么做?
FileStream stream = File.Open(@"C:\Users\Bumba\Downloads\Sample-Sales-Data.xlsx", FileMode.Open, FileAccess.Read);
IExcelDataReader excelReader = ExcelReaderFactory.CreateOpenXmlReader(stream);
DataSet result = excelReader.AsDataSet(new ExcelDataSetConfiguration() {
ConfigureDataTable = (_) => new ExcelDataTableConfiguration() {
UseHeaderRow = true
}
});
foreach (DataTable element in result.Tables) {
Console.WriteLine(element.Columns["Year"].ToString());
//what to do??????
}
excelReader.Close();
Console.ReadLine();
有人帮助......
答案 0 :(得分:3)
最简单的选择就是枚举表(表)行并将Sales_Rep_Name
列中的值与所需值(“Janet”)进行比较:
foreach (DataTable table in result.Tables)
{
foreach (DataRow row in table.Rows)
{
var salesRepName = (string)row["Sales_Rep_Name"];
if (String.Equals(salesRepName, "Janet"))
{
var year = (int)(double)row["Year"];
Console.WriteLine($"Janet's year is {year}");
}
}
}
您还可以使用DataTable.Select(string filterExpression)
方法匹配所需的行:
foreach (DataTable table in result.Tables)
{
foreach (DataRow row in table.Select("Sales_Rep_Name = 'Janet'"))
{
var year = (int)(double)row["Year"];
Console.WriteLine($"Janet's year is {year}");
}
}
第二种选择将更快(当数据很大时),但第一种选择更灵活,允许使用更复杂的过滤器。
答案 1 :(得分:0)
//Code to get an specific cell value
var asOfCell = "AB2";
var match = Regex.Match( asOfCell, @"(?<col>[A-Z]+)(?<row>\d+)" );
var colStr = match.Groups["col"].ToString();
//I rest 1 for colunm and row due to I will work with an array and it begins by zero.
var col = (int) ( colStr.Select( ( t, i ) => ( colStr[i] - 64 ) * Math.Pow( 26, colStr.Length - i - 1 ) ).Sum() ) - 1;
var rowSelected = int.Parse( match.Groups["row"].ToString() ) - 1;
var cellSelectedValue = table.Rows[rowSelected][col];