在Android中动态更新TextView

时间:2011-02-02 10:19:23

标签: android textview

我对Android开发很新。有人可以让我知道动态更新TextView(或整个屏幕)的相关API吗?

例如:我有一个搜索应用程序,我需要显示结果,而不是等待所有结果然后显示。

5 个答案:

答案 0 :(得分:22)

有几个步骤,你没有提到你知道多少你不知道多少。

假设您的UI初始结构是在res / layout中定义的,并且它在您的活动中包含TextView:

public void updateTextView(String toThis) {
    TextView textView = (TextView) findViewById(R.id.textView);
    textView.setText(toThis);
}

答案 1 :(得分:3)

如果您要将新文本设置为TextView,只需调用textView.setText(newText),其中newText是更新后的文本。每当newText发生变化时调用此方法。那是你在找什么?

答案 2 :(得分:2)

首先,您需要一个列表视图,所以

private volatile ArrayList<String>      searchResults;
ListView searchList = (ListView) findViewById(R.id.listYOURLISTVIEW);
listAdapter = new ArrayAdapter<String>(this, R.layout.blacklist, R.id.list_content, searchResults);  //blacklist is a layout to paint the fonts black
searchList.setAdapter(listAdapter);

这可能有所帮助。

private Thread refreshThread;
private boolean isRefreshing = false;

private void reinitializeRefreshThread()
{
    if (!refreshThread.equals(null)) refreshThread.stop();
    Log.d(LOGTAG+"::reinitializeRefreshThread()", "Creating new thread!\n");
    isRefreshing = true;
    refreshThread = (new Thread(new Runnable()
    {
        public void run()
        {
            Looper.prepare();
            while (isRefreshing)
            {
                //GRAB YOUR SEARCH RESULTS HERE
                //make sure the methods are synchronized
                //maybe like 
                String[] results = grabResults(); //doesn't need to be synchronized
                addResultList(results);

                Message message = myHandler.obtainMessage();
                myHandler.sendMessage(message);
                try
                {
                    Thread.sleep(2000);
                } catch (InterruptedException e)
                {
                    e.printStackTrace();
                }
                Log.d(LOGTAG+"->refreshThread", "Refresh finished!\n");
            }
        }
    }));
    Log.d(LOGTAG+"::reinitializeRefreshThread()", "Refresh thread started!\n");
    refreshThread.start();
}

final Handler myHandler = new Handler() 
{
    public void handleMessage(android.os.Message msg)   
    {
        listAdapter.notifyDataSetChanged();
    }; 
};

,其中

public synchronized void addResultList(String[] results)
{
    // remove the whole list, repopulate with new data
    searchResults.clear();
    for (int i = 0; i < results.length; i++)
    {
        addResult(results[i]);
    }
}

private synchronized void addResult(CharSequence result)
{
    if (!searchResults.contains(result.toString()))
        searchResults.add(result.toString());
    else
        Toast.makeText(getApplicationContext(), "Result " + result.toString() + " was already on the list!", Toast.LENGTH_SHORT).show();
}

所有这些都是线程安全的,这意味着它允许您通过将消息发送到UI需要更新的主线程来从主线程以外的线程“更改”GUI。如您所见,refreshThread更新搜索集合(确保方法已同步),然后通知主(UI)线程更新列表。

您可能会觉得这也很有用

searchList.setOnItemClickListener(new AdapterView.OnItemClickListener()
    {
        public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, long arg3)
        {
            listIndex = arg2;
            selectedItem = (String) searchList.getItemAtPosition(listIndex);
            Toast.makeText(getApplicationContext(), "Result[" + listIndex + "] " + selectedItem + " selected!", Toast.LENGTH_SHORT).show();
        }
    });

可能有一些松散的结局,比如你需要初始化listIndex和selectedItem或者只是把它们扔掉,但总的来说这在我非常类似的情况下为我做了伎俩(我有一个后台线程填充列表新条目的时间)

希望有所帮助:)

答案 3 :(得分:1)

尝试这个

TextView textView = (TextView)findViewById(R.id.textViewID);
textView.setText("The test you need");
view.invalidate();  // for refreshment

答案 4 :(得分:0)

如果您在另一个线程中,请确保更新UI线程内的textview。

private void updateTextView(final String s) {
    MainActivity.this.runOnUiThread(new Runnable() {
        @Override
        public void run() {
            TextView tv= (TextView) findViewById(R.id.tv);
            tv.setText("Text = "+s);
        }
    });

}