在页面加载时,我将此数据作为项目加载到模板中:
{
"id": "1",
"name": "Leonardo",
"weapon": "sword",
},
{
"height": "2",
"name": "Donatello",
"weapon": "stick",
},
我在我的组件中使用它加载数据:
this.dataSubscription = this.dataService.getAllTurtles().subscribe(res => this.turtles = res);
每个项目还有一个按钮" LOAD MORE DATA"。当我点击它时,它会加载一些属于该特定项目的额外数据:
this.dataSubscription = this.dataService.getData(id).subscribe(res => this.singleData = res);
加载我
{
"favoritePizza": "Hawai",
}
现在,我想将这些数据合并到原始数据流中,所以我有:
{
"id": "1",
"name": "Leonardo",
"weapon": "sword",
"favoritePizza": "Hawai"
},
{
"id": "2",
"name": "Donatello",
"weapon": "stick",
}
但我不确定如何以这种方式连接数组。目前我用concat做的时候:
this.dataSubscription = this.dataService.getData(id).subscribe(res => this.turtles = this.turtles.concat(res));
我只是得到了连接的数组:
{
"id": "1",
"name": "Leonardo",
"weapon": "sword",
},
{
"id": "2",
"name": "Donatello",
"weapon": "stick",
}
{
"favoritePizza": "Hawai"
}
如何使用它的ID访问数组中的特定项目并添加我稍后加载的数据?
答案 0 :(得分:1)
this.dataService.getAdditionalData(id)
.subscribe(data => {
this.turtles = this.turtles.map(i => {
if (i.id !== id) {
return i;
}
return { ...i, ...data };
})
})
示例https://stackblitz.com/edit/angular-tl4mt1?file=app%2Fapp.component.ts
答案 1 :(得分:0)
你可以做这样的事情
var a1 = [{
"id": "1",
"name": "Leonardo",
"weapon": "sword",
"favoritePizza": "Hawai"
}, {
"id": "2",
"name": "Donatello",
"weapon": "stick",
}]
var a2 = {
"favoritePizza": "Hawai",
}
a1 = a1.map((e) => {
return e.id === "1" ? Object.assign(e, a2) : e
})
console.log(a1);

虽然可能有更好的选择!!!
答案 2 :(得分:0)
也许您的通话是从按钮"加载更多数据"
完成的this.dataSubscription = this.dataService.getData(id).subscribe(res => this.singleData = res);
应该命名为
this.dataSubscription = this.dataService.getTurtle(1).subscribe(res => this.singleData = res);
使用getTurtle将Observable返回给Object Turtle,它通过设计文件包含到mongoDB中,包含Turtle的详细信息,包括最喜欢的披萨:
{
"id": "1",
"name": "Leonardo",
"weapon": "sword",
"favoritePizza": "Hawai"
}