指针和malloc在swfit

Question

我正在尝试将this转换为swift。

面对内存分配逻辑的问题

Byte *p[10000];

p[allocatedMB] = malloc(1048576);
memset(p[allocatedMB], 0, 1048576);

如何在swift中写这个？

Answer 1

你可以使用Swift中的malloc，它会返回一个“原始指针”：

var p: [UnsafeMutableRawPointer?] = Array(repeating: nil, count: 10000)
var allocatedMB = 0

p[allocatedMB] = malloc(1048576)
memset(p[allocatedMB], 0, 1048576)

或者，使用UnsafeMutablePointer及其 allocate和initialize方法：

var p: [UnsafeMutablePointer<UInt8>?] = Array(repeating: nil, count: 10000)
var allocatedMB = 0

p[allocatedMB] = UnsafeMutablePointer.allocate(capacity: 1048576)
p[allocatedMB]?.initialize(to: 0, count: 1048576)