我已按照this步骤将AWS Mobile SDK添加到我的应用中。 当我到达"连接你的后端"的第4步时部分并尝试编译我的应用程序我收到以下错误:
Error:(20, 9) error: cannot find symbol variable AWSMobileClient
我查找了文档here,发现AWSMobileClient
类应该在com.amazonaws.mobile.client.AWSMobileClient
包中,但是当我尝试手动导入提到的包时,我得到以下错误:
Error:(9, 28) error: package com.amazonaws.mobile does not exist
我当前的项目文件如下所示:
MainActivity.java
package point.cursoandroid.com.medpoint;
import android.app.Activity;
import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
public class MainActivity extends Activity {
private Button botaoLogin;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
AWSMobileClient.getInstance().initialize(this).execute();
botaoLogin = (Button) findViewById(R.id.botaoLoginId);
botaoLogin.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
startActivity(new Intent(MainActivity.this, LoginActivity.class));
}
});
}
}
app / build.gradle
apply plugin: 'com.android.application'
android {
compileSdkVersion 27
buildToolsVersion "27.0.3"
defaultConfig {
applicationId "point.cursoandroid.com.medpoint"
minSdkVersion 25
targetSdkVersion 27
versionCode 1
versionName "1.0"
}
buildTypes {
release {
minifyEnabled false
proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
}
}
}
dependencies {
compile fileTree(dir: 'libs', include: ['*.jar'])
testCompile 'junit:junit:4.12'
compile 'com.android.support:appcompat-v7:27.+'
compile 'com.android.support:support-v4:27.+'
compile 'com.android.support:design:27.+'
compile 'com.amazonaws:aws-android-sdk-core:2.6.+'
compile 'com.amazonaws:aws-android-sdk-s3:2.6.+'
compile 'com.amazonaws:aws-android-sdk-ddb:2.6.+'
}
使用AndroidStudio 3.0.1 那么,有什么想法吗?
答案 0 :(得分:9)
您需要在build.gradle中导入相应的依赖项
dependencies {
compile ('com.amazonaws:aws-android-sdk-mobile-client:2.6.+@aar') { transitive = true; }
}
执行gradle同步,您应该能够导入类和包。