按特定条件删除数组元素

Question

最好的方法是什么： 我有两个数组：

a=[['a','one'],['b','two'],['c','three'],['d','four']]

和b=['two','three']

我想删除a中包含b中元素的嵌套数组，以获取此信息：

[['a','one']['d','four']

感谢。

Answer 1

a = [['a','one'],['b','two'],['c','three'],['d','four']]
b = ['two','three']

a.delete_if { |x| b.include?(x.last) }

p a
# => [["a", "one"], ["d", "four"]]

Answer 2

rassoc救援！

 b.each {|el| a.delete(a.rassoc(el)) }

Answer 3

a=[['a','one'],['b','two'],['c','three'],['d','four']]
b=['two','three']    
result=a.reject { |e| b.include?(e.first) or b.include?(e.last) }
# result => [["a", "one"], ["d", "four"]]