Question

我有这个json-ld：

{ "@id":   "http://www.example.com/john-doe",
    "@type":   "http://xmlns.com/foaf/0.1/Person",
    "http://xmlns.com/foaf/0.1/name":   "John   Doe",
    "http://xmlns.com/foaf/0.1/age":   {
    "@value":   "42",
    "@kind":   "http://www.w3.org/2001/XMLSchema#nonNegativeInteger"},
    "http://xmlns.com/foaf/0.1/knows" : [
      {   "@id":   "http://www.example.com/charlie-brown"   },
      {   "@id":   "http://www.example.com/jane-doe"   }
    ]
  }

我必须编写上下文，以便下面的json-ld有效。

{ "@context" : "context to write....",
  "@id":   "john-doe",
  "@type":   "person",
  "name":   "John   Doe",
  "age":   "42",
  "knows":   ["charlie-brown", "jane-doe"]
}

我已经写了一个解决方案，但它不完整，我无法弄清楚如何编写完整的解决方案，希望有人可以帮助我。

Answer 1

您必须使用framing才能获得接近您要求的结果。

请参阅此答案以获取Java完整代码示例How to convert RDF to pretty nested JSON using java rdf4j。
另请参阅此答案，其中包含一些额外的标记JSON-LD to normal JSON

在json-ld playground中使用此link for an example。这是嵌入式@context的文档的样子：

{
  "@context": {
    "name": {
      "@id": "http://xmlns.com/foaf/0.1/name"
    },
    "age": {
      "@id": "http://xmlns.com/foaf/0.1/age"
    },
    "knows": {
      "@id": "http://xmlns.com/foaf/0.1/knows",
      "@container": "@set"
    }
  },
 "@id": "john-doe",
 "@type": "person",
  "name": "John   Doe",
  "age": "42",
  "knows": [
    "charlie-brown",
    "jane-doe"
  ]
}

这就是框架的外观如何

{
  "@context": {
    "name": {
      "@id": "http://xmlns.com/foaf/0.1/name"
    },
    "age": {
      "@id": "http://xmlns.com/foaf/0.1/age"
    },
    "knows": {
      "@id": "http://xmlns.com/foaf/0.1/knows",
      "@container": "@set"
    }
  }
}

这将呈现给

{
  "@context": {
    "name": {
      "@id": "http://xmlns.com/foaf/0.1/name"
    },
    "age": {
      "@id": "http://xmlns.com/foaf/0.1/age"
    },
     "knows": {
      "@id": "http://xmlns.com/foaf/0.1/knows",
      "@container": "@set"
    }
  },
  "@graph": [
    {
      "@id": "john-doe",
      "@type": "https://json-ld.org/playground/person",
      "age": "42",
      "knows": [
        "charlie-brown",
        "jane-doe"
      ],
      "name": "John   Doe"
    }
  ]
}

如何操纵Json-ld？

1 个答案: