Question

使用AJAX发布我发送数据和在其他页面上，根据此数据，我通过查询检索mysql数据库的两个不同列值。我需要通过AJAX取回这两个不同的值，并在两个不同的输入中显示。

  var mus_barkod = document.getElementById('mus_barkod').value;
  var dataString = "mus_barkod="+mus_barkod; 
    $.ajax({ 
    type: "POST", 
    url: "musteri_indir.php", 
    data: dataString, 
    success: function(result){ 

      $("#indirim").val(result.mus_indirim);
      $("#mus_isim").val(result.mus_isim);

这是AJAX的一部分，在获取数据的（OLD）查询之下：

 $mus_barkod = $_REQUEST['mus_barkod'];

 $mus_cek = mysql_query("SELECT * FROM musteriler WHERE mus_barkod = 
 '".$mus_barkod."' AND sub_id = '".$per_sube."' ");
       while ($mus_al=mysql_fetch_array($mus_cek)){

        $mus_isim   = $mus_al['mus_isim'];
        $mus_indirim= $mus_al['mus_indirim'];   
        }

 $mus_isim1 = 'Kayıtlı Müşteri Değil';
 $mus_indirim1 = '0.00';
 if($mus_barkod == '10' || $mus_barkod == '100090'|| $mus_barkod == 
 '100237')
 {
 echo 
 $mus_indirim,$mus_isim;
 }else{
 echo
 $mus_indirim1,$mus_isim1;  
 }

那么我如何能够单独回到mus_indirim和mus_isim并在不同的输入中显示？注意：不要介意mysql_，这是一个旧系统。 PDO永远：）

Answer 1

通过更仔细地检查我的代码来修复它。以下是那些需要相同解决方案的结果：

  var mus_barkod = document.getElementById('mus_barkod').value;
  var dataString = "mus_barkod="+mus_barkod; 
    $.ajax({ 
    type: "POST", 
    url: "musteri_indir.php", 
    data: dataString,
    dataType: "json",  => the little thing i forgot to write :)

    success: function(result){ 

      $("#indirim").val(result.mus_indirim);
      $("#mus_isim").val(result.mus_isim);

旧PHP：

 $mus_barkod = $_REQUEST['mus_barkod'];

 $mus_cek = mysql_query("SELECT * FROM musteriler WHERE mus_barkod = 
 '".$mus_barkod."' AND sub_id = '".$per_sube."' ");
       while ($mus_al=mysql_fetch_array($mus_cek)){

        $mus_isim   = $mus_al['mus_isim'];
        $mus_indirim= $mus_al['mus_indirim'];   
       }

 if($mus_barkod == '10' || $mus_barkod == '100090'|| $mus_barkod == 
   '100237')
 {
    echo json_encode(array("mus_indirim" => $mus_indirim, "mus_isim" => 
    $mus_isim));
 }else{
    echo json_encode(array("mus_indirim" => '0.00', "mus_isim" => 'Kayıtlı 
    Müşteri Değil'));
 }

从AJAX返回多个字符串

1 个答案: