如何在闭包中调用方法? get_access_token
方法可以根据self.get_base_url()
设置新的访问令牌:
fn fetch_access_token(_base_url: &String) -> String {
String::new()
}
fn get_env_url() -> String {
String::new()
}
pub struct App {
pub base_url: Option<String>,
pub access_token: Option<String>,
}
impl App {
pub fn new() -> App {
App {
base_url: None,
access_token: None,
}
}
pub fn get_base_url(&mut self) -> &String {
self.base_url.get_or_insert_with(|| get_env_url())
}
pub fn get_access_token(&mut self) -> &String {
self.access_token
.get_or_insert_with(|| fetch_access_token(self.get_base_url()))
}
}
fn main() {}
错误:
Rust 2015
error[E0500]: closure requires unique access to `self` but `self.access_token` is already borrowed
--> src/main.rs:26:33
|
25 | self.access_token
| ----------------- borrow occurs here
26 | .get_or_insert_with(|| fetch_access_token(self.get_base_url()))
| ^^ ---- borrow occurs due to use of `self` in closure
| |
| closure construction occurs here
27 | }
| - borrow ends here
Rust 2018
error[E0501]: cannot borrow `self.access_token` as mutable because previous closure requires unique access
--> src/main.rs:25:9
|
25 | / self.access_token
26 | | .get_or_insert_with(|| fetch_access_token(self.get_base_url()))
| |______________------------------_--____________________----________________^ second borrow occurs here
| | | |
| | | first borrow occurs due to use of `self` in closure
| | closure construction occurs here
| first borrow later used by call
error[E0500]: closure requires unique access to `self` but it is already borrowed
--> src/main.rs:26:33
|
24 | pub fn get_access_token(&mut self) -> &String {
| - let's call the lifetime of this reference `'1`
25 | self.access_token
| -----------------
| |
| _________borrow occurs here
| |
26 | | .get_or_insert_with(|| fetch_access_token(self.get_base_url()))
| |_________________________________^^____________________----________________- returning this value requires that `self.access_token` is borrowed for `'1`
| | |
| | second borrow occurs due to use of `self` in closure
| closure construction occurs here
答案 0 :(得分:3)
将您的数据和方法拆分为较小的组件,然后您可以在self
上对不同的组件进行不相交的借用:
fn fetch_access_token(_base_url: &str) -> String { String::new() }
fn get_env_url() -> String { String::new() }
#[derive(Default)]
struct BaseUrl(Option<String>);
impl BaseUrl {
fn get(&mut self) -> &str {
self.0.get_or_insert_with(|| get_env_url())
}
}
#[derive(Default)]
struct App {
base_url: BaseUrl,
access_token: Option<String>,
}
impl App {
fn new() -> App {
App::default()
}
fn get_access_token(&mut self) -> &str {
let base_url = &mut self.base_url;
self.access_token
.get_or_insert_with(|| fetch_access_token(base_url.get()))
}
}
fn main() {}
您可以进一步为两个值执行此操作:
fn fetch_access_token(_base_url: &str) -> String { String::new() }
fn get_env_url() -> String { String::new() }
#[derive(Default)]
struct BaseUrl(Option<String>);
impl BaseUrl {
fn get(&mut self) -> &str {
self.0.get_or_insert_with(|| get_env_url())
}
}
#[derive(Default)]
struct AccessToken(Option<String>);
impl AccessToken {
fn get(&mut self, base_url: &str) -> &str {
self.0.get_or_insert_with(|| fetch_access_token(base_url))
}
}
#[derive(Default)]
struct App {
base_url: BaseUrl,
access_token: AccessToken,
}
impl App {
fn new() -> App {
App::default()
}
fn get_access_token(&mut self) -> &str {
let base_url = self.base_url.get();
self.access_token.get(base_url)
}
}
fn main() {}
这使您可以看到可以抽象出常见功能:
fn fetch_access_token(_base_url: &str) -> String { String::new() }
fn get_env_url() -> String { String::new() }
#[derive(Default)]
struct StringCache(Option<String>);
impl StringCache {
fn get<F>(&mut self, f: F) -> &str
where
F: FnOnce() -> String,
{
self.0.get_or_insert_with(f)
}
}
#[derive(Default)]
struct App {
base_url: StringCache,
access_token: StringCache,
}
impl App {
fn new() -> App {
App::default()
}
fn get_access_token(&mut self) -> &str {
let base_url = self.base_url.get(get_env_url);
self.access_token.get(|| fetch_access_token(base_url))
}
}
fn main() {}
然后你意识到抽象可以变得通用:
fn fetch_access_token(_base_url: &str) -> String { String::new() }
fn get_env_url() -> String { String::new() }
#[derive(Default)]
struct Cache<T>(Option<T>);
impl<T> Cache<T> {
fn get<F>(&mut self, f: F) -> &T
where
F: FnOnce() -> T,
{
self.0.get_or_insert_with(f)
}
}
#[derive(Default)]
struct App {
base_url: Cache<String>,
access_token: Cache<String>,
}
impl App {
fn new() -> App {
App::default()
}
fn get_access_token(&mut self) -> &str {
let base_url = self.base_url.get(get_env_url);
self.access_token.get(|| fetch_access_token(base_url))
}
}
fn main() {}
另见:
答案 1 :(得分:1)
我会改用这样的东西:
echo preg_replace_callback("/[a-z]/", function ($b) use ($test) {
if (isset($b[0]) && isset($test[$b[0]]))
return $test[$b[0]];
return "";
}, "a")."\n";
答案 2 :(得分:0)
传递给Option<T>
中get_or_insert_with
方法的关闭类型为FnOnce
- 因此消耗或移动捕获的变量。在这种情况下,由于在闭包中使用了self
,因此捕获了self.get_base_url()
。但是,由于self
已被借用,因此闭包不能使用或移动self
的值以进行唯一访问。
这可以通过使用get_or_insert
方法来规避,但无论get_access_token
是否access_token
,每次调用None
时都需要您执行获取访问令牌的潜在代价高昂的操作是{{1}}。