Question

我正在尝试使用python re正则表达式匹配文本然后任何数字，除非文本是某些单词。 e.g。

# import re
import re
# this match expression is intended to match any alphanumerical word followed by any number unless the first alphanumerical word ends with either germany or france. 
match = r'[a-zA-Z0-9]{1,}[\s]{1,}(?<!france)(?<!germany)[0-9]{1,}'

re.findall( match, 'alphanumerical1234text  12312442')
>>>['alphanumerical1234text  12312442'] # this is correct

re.findall( match, 'alphanumerical1234text germany 12312442')
>>> ['germany 12312442'] # this shouldn't return anything 

re.findall( match, 'alphanumerical1234textgermany 12312442')
>>>['alphanumerical1234textgermany 12312442'] # this shouldn't return anything

re.findall( match, 'alphanumerical1234text france 12312442')
>>>['france 12312442'] # this shouldn't return anything

re.findall( match, 'alphanumerical1234textfrance 12312442')
>>>['alphanumerical1234textfrance 12312442'] # this shouldn't return anything

任何想法如何构建这个正则表达式？

Answer 1

你必须把看守放在空间之前。 …\s(?<!france)相当于…\s，因为任何以空格结尾的内容都不能以“e”结尾。

r'[a-zA-Z0-9]+(?<!france)(?<!germany)\s+[0-9]+'

正则表达式

1 个答案: