我编写了这个方法,但如果" uid"它会抛出System.ArgumentException。有'符号。
public void Init(string constr)
{
var server = "a222068_6.mysql.mchost.ru";
var database = "'a222068_6'";
var uid = "'a222068_6'@'10.0.2.13'";
var pass = "pass";
constr = "SERVER=" + server + ";DATABASE=" + database + ";UID=" + uid + ";PASSWORD=" + pass + ";SSL Mode=None;";
cnt = new MySqlConnection(constr); // Exception is thrown here
}
在没有'
的情况下尝试连接的异常消息Authentication to host 'a222068_6.mysql.mchost.ru' for user 'a222068_6@10.0.2.13' using method 'mysql_native_password' failed with message: Access denied for user 'a222068_6@10.0.2.13'@'localhost' (using password: YES)
答案 0 :(得分:0)
更改
var uid = "'a222068_6'@'10.0.2.13'";
到
var uid = @"a222068_6@10.0.2.13";
答案 1 :(得分:0)
逐字字符串文字以@开头,并且也用双引号括起来。
还有其他一些StackOverflow答案以及如何使用MySqlConnectionStringBuilder的示例,例如this one:
var connectionStringBuilder = new MySqlConnectionStringBuilder
{
Server = "<instanceIp>",
UserID = "<userId>",
Password = "<password>",
Database = "<databaseName>",
CertificateFile = @"<Path_To_The_File>\client.pfx",
CertificatePassword = "<Password_For_The_Cert>"
};
var conn = new MySqlConnection(connectionStringBuilder.ToString())