Php mysqli：更新用户，其中金额少于x并删除查询

Question

这个，它确实删除金额少于1的地方 但它没有更新用户，为什么不呢？谁能告诉我？

$data1 = mysqlI_query($link,"SELECT * FROM bubble_spends where burst <= 0");
$data  = mysqli_fetch_array($data1);

$burst123='$data[burst]';
$username123='$data[username]';
IF($data1)
{
    mysqli_query($link,"UPDATE * FROM 'users' SET 'bitcoins'='bitcoins'-'$burst123' WHERE 'username' = '$username123' ");
    mysqli_query($link,"DELETE FROM bubble_spends where amount <= 1");
}

Greets Patrick

Answer 1

1. 更新查询语法错误，查询正确

更新users设置bitcoins = bitcoins - $ burst123 WHERE username ='$ username123'

1. 从表名和列名中删除单引号（'）并改为使用tick（`）。例如更新*来自'用户'SET'比特币'='比特币' - '$ burst123'WHERERE'用户名'='$ username123'
2. 您正在使用此'$ burst123'，它被视为字符串。

更新了查询：

$data1 = mysqli_query($link,"SELECT * FROM bubble_spends where burst <= 0");
$data  = mysqli_fetch_array($data1);

$burst123='$data[burst]';
$username123='$data[username]';
IF($data1)
{
    mysqli_query($link,"UPDATE `users` SET `bitcoins`=`bitcoins`- $burst123 WHERE `username` = '$username123' ");
    mysqli_query($link,"DELETE FROM bubble_spends where amount <= 1");
}