Question

我正在向代理发送请求，我收到此错误：

{＆＃34;错误＆＃34;：{＆＃34; lang＆＃34;：＆＃34; zh-CN＆＃34;，＆＃34;说明＆＃34;：＆＃34;查询语法错误（s）[第1:68行不匹配的字符＆＃39; ＆＃39;期待＆＃39; \＆＃34;＆＃39;]＆＃34;}}

这是网址：

https://query.yahooapis.com/v1/public/yql?q=SELECT%20*%20FROM%20json%20WHERE%20url=%22https://1ex.trade/api/stats?market=BTC&currency=CHBT%22&format=json

有没有人知道我做错了什么？

这是我在JS的请求

let fetchRequestForGettingTheNamesTroughProxy = function (exchangeUrl) {
     return new Promise(function (resolve, reject) {
         const url = exchangeUrl;
         const yql_url = 'https://query.yahooapis.com/v1/public/yql?q=' + 'SELECT * FROM json WHERE url="' + url + '"&format=json';
         let request = new Request(yql_url, {
             method: 'POST',
             headers: new Headers()
         });
         fetch(request)
             .then((resp) => resp.json())
             .then(function (data) {
                 console.log(data.query.results);
                 if (data.query.results === null){
                     fetchRequestForGettingTheNamesTroughProxy(exchangeUrl);
                 } else{
                     resolve(data.query.results.json);
                 }
             });
     });
 };

Answer 1

您没有正确编码您应该看起来像

的网址

https://query.yahooapis.com/v1/public/yql?q=SELECT%20*%20FROM%20json%20WHERE%20url=%27https%3A%2F%2F1ex.trade%2Fapi%2Fstats%3Fmarket%3DBTC%26currency%3DCHBT%27&format=json

所以请使用encodeURIComponent

const yql_url = 'https://query.yahooapis.com/v1/public/yql?q=' + 'SELECT * FROM json WHERE url="' + encodeURIComponent(url) + '"&format=json';

Answer 2

我认为您需要正确编码url参数
exchangeUrl中的＆符号（＆amp;）会破坏q参数，从而中断您的查询。

const yql_url = 'https://query.yahooapis.com/v1/public/yql?q=' + 
                'SELECT * FROM json WHERE url="' + encodeURIComponent(url) + 
                '"&format=json';

Answer 3

＆amp;在您的q网址中需要进行编码。

EG：

https://query.yahooapis.com/v1/public/yql?q=SELECT%20*%20FROM%20json%20WHERE%20url=%22https://1ex.trade/api/stats?market=BTC%26currency=CHBT%22&format=json

不匹配的角色＆＃39; ＆＃39;期待＆＃39; \＆＃34;＆＃39;

3 个答案: