请帮我解决这个问题,我试着从上周开始解决这个问题。使用cordova文件传输插件尝试将我的图像上传到生产服务器 但是我得到错误代码1.
我检查了源和目标路径都可以访问。请找到我的cordova安装版本。
Cordova - > 7.1.0, Phonegap - > 7.1.1, cordova-plugin-file-transfer - >规格= 1.7.1
代码:
function staticpathu_upload() {
var fileURL = 'https://example.com/Al_2_1518090802.jpg';
var uri = encodeURI('https://example.com/dummy.php');
var options = new FileUploadOptions();
options.fileKey = "file";
options.fileName = fileURL.substr(fileURL.lastIndexOf('/')+1);
options.mimeType = "image/jpeg";
var ft = new FileTransfer();
ft.upload(fileURL, uri, onSuccess, onError, options);
function onSuccess(r) {
console.log("Code = " + r.responseCode);
console.log("Response = " + r.response);
console.log("Sent = " + r.bytesSent);
}
function onError(error) {
console.log(error);
alert("An error has occurred: Code = " + error.code);
console.log("upload error source " + error.source);
console.log("upload error target " + error.target);
}
}

错误:
FileTransferError {
code: 1,
source: "https://example.com/Al_2_1518090802.jpg",
target: "https://example.com/dummy.php",
http_status: null,
body: null,
}
答案 0 :(得分:0)
fileUrl
必须是
表示设备上的文件或数据URI的文件系统URL。为了向后兼容,这也可以是设备上文件的完整路径。 (参见下面的向后兼容性说明)
请参阅the docs
这可能是抛出FileTransferError.FILE_NOT_FOUND_ERR
(错误代码1)的原因。
答案 1 :(得分:0)
ServerUrl的这个问题,它不允许我将图像发布到服务器。我在服务器根文件夹上创建了dummy.php,并从下面的代码执行它工作正常。它不适用于我们仅在移动设备或模拟器中检查的桌面。
function uploadphoto(){
navigator.camera.getPicture(uponSuccess, uponFail, { quality: 50,
sourceType: Camera.PictureSourceType.PHOTOLIBRARY,
allowEdit: true,
destinationType: Camera.DestinationType.FILE_URI
});
// Change image source and upload photo to server
function uponSuccess(imageURI) {
// Set image source
var image = document.getElementById('fileuploadimg');
$$('.gAlbumList').append('<a href="#"><img src="'+imageURI + '?' + Math.random()+'" /></a>');
var options = new FileUploadOptions();
options.fileKey = "file";
options.fileName = imageURI.substr(imageURI.lastIndexOf('/') + 1);
options.mimeType = "image/jpeg";
var params = {};
params.value1 = "test";
params.value2 = "param";
options.params = params;
options.chunkedMode = false;
var ft = new FileTransfer();
ft.upload(imageURI, "https://example.com/dummy.php", function(result){
$$('.error').append('<p>successfully uploaded ' + result.response+'</p>');
}, function(error){
$$('.error').append('<p>error : ' + JSON.stringify(error)+'</p>');
}, options);
}
function uponFail(message) {
$$('.error').append('<p>Failed because: ' + message+'</p>');
}