Question

我不明白如何传递包含表数据的对象数组，当模型查询返回时，这是存储在一个变量中。

所以帮帮我......

我花费更多时间来处理此错误，以便任何人对此错误有所了解

错误：

未定义变量：data文件名：employee / view_Admin_Profile.php 行号：164

行是<?php echo ($data->sub_dept_name);?>

contoller：

public function update_Admin_Profile($emp_id)
    {   

        $data = $this->Loginm->getEmployeeProfile($emp_id);
        $this->load->view('admin/header',$data);
        $this->load->view('admin/sidebar',$data);
        $this->load->view('employee/update_Admin_Profile',$data);
        $this->load->view('admin/footer');
   }

视图：

<div class="col-md-12">
                    <div class="form-group"> 
                        <label class="col-lg-4 control-lable">Gendar:</label>
                        <div class="col-lg-8">
                          <?php echo ($data->gender);?>
                        </div>    
                    </div>
                 </div>


                <div class="col-md-12">
                    <div class="form-group"> 
                        <label class="col-lg-4 control-lable">Department Name:</label>
                        <div class="col-lg-8">
                        <?php echo ($data->sub_dept_name);?>
                        </div>    
                    </div>
                </div>

                <div class="col-md-12">
                    <div class="form-group"> 
                        <label class="col-lg-4 control-lable">Role:</label>
                        <div class="col-lg-8">
                        <?php echo ($getEmpProfile->role_name);?>
                        </div>    
                    </div>
                </div>

                <div class="col-md-12">
                    <div class="form-group"> 
                        <label class="col-lg-4 control-lable">Nationality:</label>
                        <div class="col-lg-8">
                          <?php echo ($data->nationality);?>
                        </div>    
                    </div>
                 </div>

型号：

public function getEmployeeProfile($emp_id)
        {
            $this->db->select('*');
            $this->db->from('employee e');
            $this->db->join('sub_department sd','sd.sub_dept_id = e.sub_dept_id','left');
            $this->db->join('department d','d.dept_id = sd.dept_id','left');
            $this->db->join('user_role ur','ur.role_id = e.role_id','left');
            $this->db->where('e.emp_id',$emp_id);

            $query=$this->db->get();

            if($query->num_rows() > 0)
            {
                return $query->row();
            }
        }

Answer 1

    public function update_Admin_Profile($emp_id)
    {   

        //$data = $this->Loginm->getEmployeeProfile($emp_id); Your Code
        $data['data'] = $this->Loginm->getEmployeeProfile($emp_id); //Change to this line
        $this->load->view('admin/header',$data);
        $this->load->view('admin/sidebar',$data);
        $this->load->view('employee/update_Admin_Profile',$data);
        $this->load->view('admin/footer');
   }

  and in view you can fetch like the following code:
 <?php echo ($data[0]->sub_dept_name);?>

Answer 2

我们举个例子：您正从模型中获取数据，

$data = array('gender' => 'male', 'age' => 22)

然后要在codeigniter视图中访问，您需要将数组的键作为变量进行回显例如：

<?php echo $gender; ?>

如何传递对象数组来查看？ MVC ..在Codeigniter

2 个答案: