产品表格结构和数据 -
id,product_name,hsn,product_category,product_subcategory,company, pic,part_no,min_stock,stock,rate,notes
product_subcategory列包含类似于例如
的值13,14,31,138
18
126,140,176,177
78,79
以上数字是下表的ID
product_subcategory
-
id,subcategory_name
创建发票时,我需要通过product_category, product_subcategory, company
的组合搜索产品。
为此,我有如下的ajax
<?php
$script2 = <<< JS
$(document).ready(function () {
$(document.body).on('change', '#purchaseitems-0-category_id, #purchaseitems-0-model_id, #purchaseitems-0-company_id', function () {
var tt = $("#purchaseitems-0-category_id").val();
var tt2 = $("#purchaseitems-0-model_id").val();
var tt3 = $("#purchaseitems-0-company_id").val();
var stuff1 ={'key1': tt ,'key2': tt2, 'key3': tt3};
p1();
});
});
function p1() {
var stuff ={'key1':$("#purchaseitems-0-category_id").val(),'key2':$("#purchaseitems-0-model_id").val(), 'key3': $("#purchaseitems-0-company_id").val()};
$.ajax({
type: "POST",
url: "http://localhost/yii-application/backend/web/index.php?r=purchase/p1",
data: {result:JSON.stringify(stuff)},
success: function (test4) {
var json_obj5 = $.parseJSON(test4);
$('#purchaseitems-0-name_of_product').val(json_obj5.id);
$('#purchaseitems-0-hsn').val(json_obj5.hsn);
$('#purchase-taxrate').val(json_obj5.rate);
$('#purchaseitems-0-part').val(json_obj5.part_no);
},
error: function (exception) {
alert(exception);
}
});
}
JS;
$this->registerJs($script2);
?>
现在需要更改的真实代码 -
public function actionP1()
{
$data2 = Yii::$app->request->post('result');
$data = $_POST["result"];
$data = json_decode("$data", true);
if (isset($data)) {
$test = $data;
$modelfedbkshiprate = \backend\models\Product::find()->where(['product_category' => $data["key1"]])->andWhere(['like' , 'product_subcategory' , $data["key2"]])->andWhere(['company' => $data["key3"]])->one();
} else {
$test = "Ajax failed";
}
return \yii\helpers\Json::encode($modelfedbkshiprate);
}
上述问题的问题是like
中的 product_subcategory
运算符。
like
运算符搜索id 7
而不是78
,因此我最终得到了错误的产品。我想过使用FIND_IN_SET
但不知道怎么做。
请为like
运营商建议替代解决方案。
答案 0 :(得分:1)
你需要使用FIND_IN_SET
来实现这一点,因为我知道你在product_subcategory
字段中有逗号分隔的值,并且你想获得具有通过其传递的特定id的行您SQL
查询的表单。
因此,您需要使用\yii\db\Expression
子句中的where
,如下所示。
\backend\models\Product::find()
->where(['product_category' => $data["key1"]])
->andWhere(new \yii\db\Expression('FIND_IN_SET(:cat_to_find,product_subcategory)'))
->andWhere(['company' => $data["key3"]])
->addParams([':cat_to_find' => $data["key2"]])
->one();
你的行动应该是这样的
public function actionP1()
{
$data2 = Yii::$app->request->post('result');
$data = $_POST["result"];
$data = json_decode("$data", true);
if (isset($data)) {
$test = $data;
$modelfedbkshiprate = \backend\models\Product::find()->where(['product_category' => $data["key1"]])->andWhere(new \yii\db\Expression('FIND_IN_SET(:cat_to_find,product_subcategory)'))->andWhere(['company' => $data["key3"]])->addParams([':cat_to_find' => $data["key2"]])->one();
} else {
$test = "Ajax failed";
}
return \yii\helpers\Json::encode($modelfedbkshiprate);
}
答案 1 :(得分:0)
关注此(Find_In_SET)对我有用。
Categories::find()->where(new Expression('FIND_IN_SET(:category_to_find, categories)'))->addParams([':category_to_find' => 3])->asArray()->all();