我有一个查询可以选择'2017-01-01'和'2017-03-01'之间的日期计数 无论如何都要单独计算“2017-01-01”,“2017-02-01”和“2017-03-01”而不使用案例陈述。
像使用分组
答案 0 :(得分:1)
您需要功能date_trunc
。它会将您的日期/时间戳截断为月份。
daniel=> select date_trunc('month', '2017-01-31'::date);
date_trunc
---------------------
2017-01-01 00:00:00
(1 row)
daniel=> select date_trunc('month', '2017-03-17'::date);
date_trunc
---------------------
2017-03-01 00:00:00
(1 row)
即。查询将类似于:
SELECT
date_trunc('month', date) as 'month',
count(*) as 'count'
FROM
table
WHERE
date_trunc('month', date) >= '2017-01-01'
AND
date_trunc('month', date) <= '2017-03-01'
GROUP BY
date_trunc('month', date);
如果您需要生成时间序列,请使用row_number() over ()
和任何有足够行的表格,例如system_tables
:
daniel=> select '2017-01-01'::DATE + cast(row_number() over () - 1 as interval month) from system_tables limit 5;
?column?
---------------------
2017-01-01 00:00:00
2017-02-01 00:00:00
2017-03-01 00:00:00
2017-04-01 00:00:00
2017-05-01 00:00:00
(5 rows)
您也可以尝试TIMESERIES
填空:
SELECT ts AS 'date' FROM (
SELECT '2017-01-01'::TIMESTAMP AS tm
UNION
SELECT '2017-01-03'::TIMESTAMP AS tm) AS t
TIMESERIES ts AS '8 hours' OVER (ORDER BY tm);
daniel=> \e
date
---------------------
2017-01-01 00:00:00
2017-01-01 08:00:00
2017-01-01 16:00:00
2017-01-02 00:00:00
2017-01-02 08:00:00
2017-01-02 16:00:00
2017-01-03 00:00:00
(7 rows)
现在,让我们将所有内容合并在一起,并使用date_trunc
计算每月的天数:
SELECT
date_trunc('month', T.date) AS 'MONTH',
count(*) AS 'COUNT'
FROM (
SELECT ts::DATE AS 'date' FROM (
SELECT '2017-01-01'::TIMESTAMP AS tm
UNION ALL
SELECT '2017-03-01'::TIMESTAMP AS tm
) AS S
TIMESERIES ts AS '8 hours' OVER (ORDER BY tm)
) AS T
GROUP BY 1
ORDER BY 1;
daniel=> \e
MONTH | COUNT
---------------------+-------
2017-01-01 00:00:00 | 93
2017-02-01 00:00:00 | 84
2017-03-01 00:00:00 | 1
(3 rows)
答案 1 :(得分:0)
#!/bin/sh
#SBATCH -N 1
#SBATCH -n 1
#SBATCH -c 4
#SBATCH --mem=10
#SBATCH -t 0:01:00
module load python
python main.py
或者您可以更改日期包含或独占