Question

我收到MY ajax的回复如下

"{\"analgesicTax\":false,\"unitPriceRequired\":false,\"toConsumer\":true,\"toRetailer\":true,\"taxName\":\"1\"}"

调用JSON.parse(result)后，结果如下所示

{"analgesicTax":false, "unitPriceRequired":false, "toConsumer":true, "toRetailer":true, "taxName":"1"}

直到那一刻，一切似乎都没问题。但是，当我尝试使用以下代码

打印我的键/值对时

 var data =  JSON.parse(result);
                    console.log(data);
                    console.log(data.analgesicTax);
                    for (var prop in data) {
                    console.log(prop+"is" + data[prop]);

我尝试使用有和没有JSON.parse()但输出如下。

0is{
1is"
2isa
3isn
4isa
5isl
6isg
7ise
8iss
9isi
10isc
11isT
12isa
13isx
14is"
15is:
16isf
17isa
18isl
19iss
20ise
21is,
22is"
23isu
24isn
25isi
26ist
27isP
28isr
29isi
30isc
31ise
32isR
33ise
34isq
35isu
36isi
37isr
38ise
39isd
40is"
41is:
42isf
43isa
44isl
45iss
46ise
47is,
48is"
49ist
50iso
51isC
52iso
53isn
54iss
55isu
56ism
57ise
58isr
59is"
60is:
61ist
62isr
63isu
64ise
65is,
66is"
67ist
68iso
69isR
70ise
71ist
72isa
73isi
74isl
75ise
76isr
77is"
78is:
79ist
80isr
81isu
82ise
83is,
84is"
85ist
86isa
87isx
88isN
89isa
90ism
91ise
92is"
93is:
94is"
95is1
96is"
97is}

在我看来，它不是像JSON对象那样对待它，而是作为字符串数组处理。任何输入？

Answer 1

如果result已经是JSON，那么您不想使用JSON.parse()，因为JSON.parse()会将JSON的字符串表示转换为对象。只需在编码时运行for循环，就可以获得所有键及其值。

但是，如果你开始使用JSON对象的字符串表示，那么当你想使用JSON.parse()时就是这样。

＆＃13;

//Starting with a JSON object
var result = {
  "analgesicTax": false,
  "unitPriceRequired": false,
  "toConsumer": true,
  "toRetailer": true,
  "taxName": "1"
}

for (var prop in result) {
  console.log(prop + " is " + result[prop]);
}

console.log('');

//Starting with JSON represented as a string
var result = "{\"analgesicTax\":false,\"unitPriceRequired\":false,\"toConsumer\":true,\"toRetailer\":true,\"taxName\":\"1\"}";

var data = JSON.parse(result);

for (var prop in data) {
  console.log(prop + " is " + data[prop]);
}

＆＃13;

Answer 2

试试这个。

- (void)viewDidLoad {
     [super viewDidLoad];
}

- (IBAction)actionLogin:(id)sender {
     [self loginForGettingAccessandRefreshToken];
}

-(void)loginForGettingAccessandRefreshToken
{
  @try {

         NSString *strUserName = [textUsername.text stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
         NSString *strPassword = [textPassword.text stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];

         NSString *strParameters = [NSString stringWithFormat:@"client_id=roclient&client_secret=secret&grant_type=password&username=%@&password=%@&scope=dataEventRecords offline_access", strUserName, strPassword];

        id param = strParameters;
        NSLog(@"The param is - %@",param);

       [GlobalShareClass postLoginDataToServer:BASEURL_LOGIN passParameters:param success:^(id res)
       {
           if([res isKindOfClass:[NSDictionary class]]){

            NSDictionary *dictRes = [res copy];
            NSString *strErrDesc = [NSString stringWithFormat:@"%@",[dictRes objectForKey:@"error_description"]];

            if([[dictRes allKeys] containsObject:@"error_description"]){
             dispatch_async(dispatch_get_main_queue(), ^{

                  //Dispaly UI
             });
         }
         else{
              NSString *strAccessToken = [dictRes objectForKey:@"access_token"];
             NSString *strRefreshToken = [dictRes objectForKey:@"refresh_token"];
             NSString *strTokenType = [dictRes objectForKey:@"token_type"];
             NSString *sstrExpiresIn = [dictRes objectForKey:@"expires_in"];

             [[NSUserDefaults standardUserDefaults] setObject:globalShare.strRefreshToken forKey:@"refresh_token"];
             [[NSUserDefaults standardUserDefaults] setObject:globalShare.strAccessToken forKey:@"access_token"];
             [[NSUserDefaults standardUserDefaults] synchronize];

             NSDictionary *responseDict = [GlobalShareClass getDataFromToken:globalShare.strAccessToken];


             NSString *strFetchedSub = [[NSUserDefaults standardUserDefaults] stringForKey:@"loginIdSub"];


             globalShare.loginId = [responseDict objectForKey:@"sub"];

        }
      }
      else{
         NSLog(@"The res starts with array");
      }


 } failure:^(NSError *error) {
     // error handling here ...
     NSLog(@"%@", [error localizedDescription]);
     dispatch_async(dispatch_get_main_queue(), ^{
        //Showing Error
     });
 } passViewController:self];
}
@catch(NSException *exception){
    NSLog(@"%@",[exception description]);
}
@finally{

}
}
}

迭代JSON不工作jQuery

2 个答案: