我一直试图将XML文件放入数据框但是我正在努力,我尝试了一些方法,这就是我所处的位置。
我的XML文件看起来像20k段:
<?xml version="1.0"?>
<data experimentId="5244" savingTime="2018-01-06T14:25:48-0500" eventType="Workflow" userId="303">
<root>
<set id="ASSAY_WORKFLOW">
<row state="MODIFIED" pk="5905_Standard_Validation_Standard_Validation">
<field name="ASSAY_ID">5244</field>
<field name="WORKFLOW_ID">5905_Standard_Validation_Standard_Validation</field>
<field name="WORKFLOW_STATE">0</field>
<field name="ASSAY_WORKFLOW_STATE">InDelegation</field>
<field name="WORKFLOW_LAST_STEP_ID">17896</field>
</row>
</set>
<set id="WORKFLOW_STEPS">
<row state="NEW" pk="17896">
<field name="STEP_ID">17896</field>
<field name="WORKFLOW_ID">5905_Standard_Validation_Standard_Validation</field>
<field name="STEP_DATE">2018-01-06T14:25:45-0500</field>
<field name="STEP_DATE_TZ">America/New_York</field>
<field name="USER_ID">303</field>
<field name="USER_FULL_NAME">Ron Swanson</field>
<field name="NEW_WORKFLOW_ASSAY_STATE">InDelegation</field>
<field name="FORMER_WORKFLOW_ASSAY_STATE">Draft</field>
<field name="ROLE_ID">1</field>
</row>
</set>
<set id="WORKFLOW_STEP_VARIABLES">
<row state="NEW" pk="17896¤nextActorId">
<field name="STEP_ID">17896</field>
<field name="VARIABLE_ID">nextActorId</field>
<field name="VALUE">2</field>
</row>
<row state="NEW" pk="17896¤validateToPendingValidation">
<field name="STEP_ID">17896</field>
<field name="VARIABLE_ID">validateToPendingValidation</field>
<field name="VALUE">false</field>
</row>
<row state="NEW" pk="17896¤signToPendingSignature">
<field name="STEP_ID">17896</field>
<field name="VARIABLE_ID">signToPendingSignature</field>
<field name="VALUE">false</field>
</row>
<row state="NEW" pk="17896¤comment">
<field name="STEP_ID">17896</field>
<field name="VARIABLE_ID">comment</field>
<field name="VALUE">GH-VAP, IgG1 repeats,</field>
</row>
<row state="NEW" pk="17896¤actionDelegateU">
<field name="STEP_ID">17896</field>
<field name="VARIABLE_ID">actionDelegateU</field>
<field name="VALUE">directDelegateU</field>
</row>
</set>
<set id="WORKFLOW_ROLE_NAMES">
<row state="NEW" pk="1">
<field name="ROLE_ID">1</field>
<field name="LANGUAGE_ID">2</field>
<field name="DESCRIPTION">Author</field>
</row>
</set>
</root>
</data>
对于每个根节点,都有子元素具有相同的标记“field”,其属性为“name”。其值在我的数据框中标识我想要的列的值和名称。
我可以用这个来解决所有问题:
library(XML)
xmlfilealt <- xmlParse("data/eln_audit_workflow.xml")
username <- xpathSApply(xmlfilealt, "//field[@name='USER_FULL_NAME']", xmlValue)
title <- xpathSApply(xmlfilealt, "//field[@name='VALUE']", xmlValue)
state <- xpathSApply(xmlfilealt, "//field[@name='ASSAY_WORKFLOW_STATE']", xmlValue)
actionDate <- xpathSApply(xmlfilealt, "//field[@name='STEP_DATE']", xmlValue)
actor <- xpathSApply(xmlfilealt, "//field[@name='DESCRIPTION']", xmlValue)
我计划用它们创建一个data.frame但是这些向量都是略微不同的长度我假设是因为某些根节点中可能存在一些缺少的元素。有人能告诉我如何处理这个问题吗?
由于
答案 0 :(得分:2)
对于可能存在或不存在的子元素,请考虑按节点位置在父节点(此处为<row>
)上进行迭代。然后,使用XPath的concat
构建将每列投射到所需值或零长度字符串的数据帧列表,以始终返回相等长度列的结果。最后rbind
最终列表的所有数据帧。
row_length <- length(xpathSApply(xmlfilealt, "//row"))
df_List <- lapply(seq(row_length), function(i){
data.frame(
username = xpathSApply(xmlfilealt, sprintf("concat(//row[%s]/field[@name='USER_FULL_NAME'],'')", i), xmlValue),
title = xpathSApply(xmlfilealt, sprintf("concat(//row[%s]/field[@name='VALUE'],'')", i), xmlValue),
state = xpathSApply(xmlfilealt, sprintf("concat(//row[%s]/field[@name='ASSAY_WORKFLOW_STATE'],'')", i), xmlValue),
actionDate = xpathSApply(xmlfilealt, sprintf("concat(//row[%s]/field[@name='STEP_DATE'],'')", i), xmlValue),
actor = xpathSApply(xmlfilealt, sprintf("concat(//row[%s]/field[@name='DESCRIPTION'],'')", i), xmlValue),
stringsAsFactors = FALSE
)
})
# CONCATENATE ALL DFs
finaldf <- do.call(rbind, df_List)
# CONVERT ZERO-LENGTH STRINGS TO NA
finaldf[] <- sapply(finaldf, function(col) ifelse(col=='', NA, col))
finaldf
# username title state actionDate actor
# 1 Ron Swanson 2 InDelegation 2018-01-06T14:25:45-0500 Author
# 2 <NA> false <NA> <NA> <NA>
# 3 <NA> false <NA> <NA> <NA>
# 4 <NA> GH-VAP, IgG1 repeats, <NA> <NA> <NA>
# 5 <NA> directDelegateU <NA> <NA> <NA>
# 6 <NA> <NA> <NA> <NA> <NA>
# 7 <NA> <NA> <NA> <NA> <NA>
# 8 <NA> <NA> <NA> <NA> <NA>
答案 1 :(得分:1)
此xml非常不一致,难以以一致的方式解析。我更喜欢使用xml2包,因为我发现语法更容易使用。
library(xml2)
# parse all of the root nodes into separate nodes
rootnodes<-xml_find_all(page, "root")
# read the desired fields from each individual root nodes
a<-sapply(rootnodes, function(xnode) { xml_text(xml_find_first(xnode, "set/row/field[@name='ASSAY_WORKFLOW_STATE']"))})
b<-sapply(rootnodes, function(xnode) { xml_text(xml_find_first(xnode, "set/row/field[@name='STEP_DATE']"))})
c<-sapply(rootnodes, function(xnode) { xml_text(xml_find_first(xnode, "set/row/field[@name='USER_FULL_NAME']"))})
d<-sapply(rootnodes, function(xnode) { xml_text(xml_find_first(xnode, "set/row/field[@name='DESCRIPTION']"))})
#Create the desired output
df=data.frame(assaystate = a, stepdate=b, name = c, description = d)
这种方法的优点是每个根节点的期望应包含每个所需的字段。如果缺少该字段/节点,则xml2的xml_find_first将返回NA,因此所有结果的大小都相同。
我省略了值字段,因为至少有带属性值的字段,并且不清楚是否需要其中一个或所有值。