Question

所以在我的程序的主要部分有一个部分，我调用hailstone函数来回答print语句中的问题。而不是打印序列一次，它打印两次，我不知道为什么或如何解决它。有没有办法解决这个问题并从函数next（n）中删除print语句？另外，我想知道我的评论是否合适？我很难写出合适的合同，所以对这些合同的任何提示和批评都会很棒。但主要的是让冰雹序列打印一次，而不是两次。

// Program hailstone takes a number and gives a sequence of 
// numbers starting with the input(n). The sequence alogrithm
// is (3n+1) then the next number is the previous divided by two.


#include <cstdio>
using namespace std;

// The function next(n)takes an integer value n and 
// returns the number that follows n in a hailstone sequence. 
// For example: next(7) = 22 and next(22) = 11.

int next(int n)
{
  if (n > 1)
  {            
    if ((n % 2) == 0 )
    {
      n = n / 2;
    }
      else
      {
        n = 3 * n + 1;
      }   
     printf("%i ",n); 
  }          
  return n;
}

// The function hailstone reads int n and 
// prints its entire hailstone sequence.

void hailstone(int n)
{
  while(n>1)
  {
    n = next(n);
  }
} 

// Parameters: int length, int n
// Uses next function, to calculate the length of the sequence.
int length(int n)
{
    int length = 1;
    while (n > 1)
    {
        n = next(n);
        ++length;
    }
    return length;
} 

int main()
{
  int n; 

  printf("What number shall I start with? ");
  scanf("%i", &n);

  printf("The hailstone sequence starting at %i is:", n);
  hailstone(n);

  printf("\nThe length of the sequence is: %i", length(n));

  return 0;
}

Answer 1

不要把打印声明放在下一个。把它放在冰雹里。它出现了两次，因为它是从冰雹上打印过一次而且是从长度上打印过一次。

我正在计算的序列（hailstone）在需要打印一次时打印两次

1 个答案: